我如何将char *插入结构数组？

Question

任务是为结构数组动态分配内存，然后从键盘填充它们。我能够为数组中的每个struct实例动态分配和填充页面数量，但是当我尝试通过执行类似以下操作向其中添加char *时：strcpy(myArray[i]->author, authorName);

但是每次我遇到细分错误时，我在做什么错呢？问题可能出在内存分配中吗？

这里是代码

#include <stdlib.h>
#include <string.h>

struct Book {
    char* author;
    char* title;
    int pages;
    int pubYear;
    int copies;
};

void allocList(struct Book **myArray, int booksAmount);
void fillKeyboard(struct Book **myArray, int booksAmount);

int main(void) {

    struct Book *booksList = NULL;

    int booksAmount = 3;

    allocList(&booksList, booksAmount);

    fillKeyboard(&booksList, booksAmount);

  return 0;
}

void allocList(struct Book **myArray, int booksAmount) {
    *myArray = (struct Book*) malloc(sizeof(struct Book) * 100);
    printf("memory for %d books was allocated \n", booksAmount);
}

void fillKeyboard(struct Book **myArray, int booksAmount) {

    int i = 0;

    char* authorName = "author name";

    while (booksAmount--) {
        printf("book number %d \n", i + 1);
        printf("enter amount of pages: ");
        scanf("%d", &(*myArray)[i].pages);
        printf("\nenter author: ");
        strcpy(myArray[i]->author, authorName);
        printf("%s is \n", authorName);
        i++;
        printf("\n");
    }

}

谢谢。

Answer 1

myArray[i].author=malloc(sizeof(char) * 100);

您的while循环应如下所示：

 while (booksAmount--) {
    myArray[i].author=malloc(sizeof(char) * 100);
    printf("book number %d \n", i + 1);
    printf("enter amount of pages: ");
    scanf("%d", &(myArray)[i].pages);
    printf("\nenter author: ");
    strcpy(myArray[i].author, authorName);
    printf("%s is \n", authorName);
    i++;
    printf("\n");
}

请记住，100是一个“魔术数字”，因此，如果作者姓名超过100个字符，那么它将不起作用

编辑：与标题相同，您需要在数组的元素中分配所需的内存

Answer 2

struct Book {
    char* author;
    char* title;
    int pages;
    int pubYear;
    int copies;
    struct Book *next;
};

程序当然会复杂一些，但是结果是干净的内存使用和真正的动态程序。