如何在以逗号分隔的键分隔的数组中排序

Question

如何在以键分隔的单个数组内排序为日期，并以逗号分隔值。

旧版时间序列正在以以下格式发送数据

arr1 = ['3/13/20,2179','3/14/20,2727', '3/14/20,1024' , '3/14/20,3020', '3/13/20,100', '3/13/20,190']

我正在努力按以下格式对其进行排序，关键是按所有必需值分组的日期

arr1 = [3/13/20,2179,100,190,3/14/20,2727,1024,3020]

任何指针/提示都会有所帮助。

Answer 1

重复日期，split key以获取date和count。如果要按日期排序，请分割date-string。并在排序回调函数中返回比较的差异。

const arr1 = [
  "3/13/20,2179",
  "3/14/20,2727",
  "3/14/20,1024",
  "3/14/20,3020",
  "3/13/20,100",
  "3/13/20,190",
];
const sort = (data) => {
  return data.sort((x, y) => {
    const [date, num] = x.split(",");
    const [date1, num1] = y.split(",");
    const [mm, dd, yy] = date.split("/");
    const [mm1, dd1, yy1] = date1.split("/");
    return new Date(dd, mm, yy).getTime() - new Date(dd1, mm1, yy1).getTime();
  });
};
console.log(sort(arr1));

根据日期排序然后计数
 
arr1 = [
  "3/13/20,2179",
  "3/14/20,2727",
  "3/14/20,1024",
  "3/14/20,3020",
  "3/13/20,100",
  "3/13/20,190",
];
const sort = (data) => {
  return data.sort((x, y) => {
    const [date, num] = x.split(",");
    const [date1, num1] = y.split(",");
    const [mm, dd, yy] = date.split("/");
    const [mm1, dd1, yy1] = date1.split("/");
    const d1 = new Date(dd, mm, yy).getTime();
    const d2 = new Date(dd1, mm1, yy1).getTime();
    if (d1 !== d1) return d1 - d2;
    return Number(num) - Number(num1);
  });
};
console.log(sort(arr1));