我有一个像下面这样的json:
{
"d": {
"results": [
{
"__metadata": {
},
"prop1": "value1",
"prop2": "value2",
"__some": "value"
},
{
"__metadata": {
},
"prop3": "value1",
"prop4": "value2",
"__some": "value"
},
]
}
}
我只想将此JSON转换为其他JSON。我想从JSON中删除“ _ 元数据”和“ _ some”节点。我正在使用JSON.NET。
我最终反序列化到JObject,然后递归地循环遍历以删除不需要的字段。这是那些有兴趣的人的功能。
private void removeFields(JToken token, string[] fields)
{
JContainer container = token as JContainer;
if (container == null) return;
List<JToken> removeList = new List<JToken>();
foreach (JToken el in container.Children())
{
JProperty p = el as JProperty;
if (p != null && fields.Contains(p.Name))
{
removeList.Add(el);
}
removeFields(el, fields);
}
foreach (JToken el in removeList)
{
el.Remove();
}
}
基于@ [Mohamed Nuur]的答案,我将其更改为我认为效果更好的扩展方法:
public static JToken RemoveFields(this JToken token, string[] fields)
{
JContainer container = token as JContainer;
if (container == null) return token;
List<JToken> removeList = new List<JToken>();
foreach (JToken el in container.Children())
{
JProperty p = el as JProperty;
if (p != null && fields.Contains(p.Name))
{
removeList.Add(el);
}
el.RemoveFields(fields);
}
foreach (JToken el in removeList)
{
el.Remove();
}
return token;
}
这里是单元测试:
[TestMethod]
public void can_remove_json_field_removeFields()
{
string original = "{\"d\":{\"results\":[{\"__metadata\":{},\"remove\":\"done\",\"prop1\":\"value1\",\"prop2\":\"value2\",\"__some\":\"value\"},{\"__metadata\":{},\"prop3\":\"value1\",\"prop4\":\"value2\",\"__some\":\"value\"}],\"__metadata\":{\"prop3\":\"value1\",\"prop4\":\"value2\"}}}";
string expected = "{\"d\":{\"results\":[{\"prop1\":\"value1\",\"prop2\":\"value2\",\"__some\":\"value\"},{\"prop3\":\"value1\",\"prop4\":\"value2\",\"__some\":\"value\"}]}}";
string actual = JToken.Parse(original).RemoveFields(new string[]{"__metadata", "remove"}).ToString(Newtonsoft.Json.Formatting.None);
Assert.AreEqual(expected, actual);
}
我将创建仅包含所需信息的新数据结构,并从第一个数据中复制数据。通常这是最简单的方法。只是一个想法。
此答案适用于具有JTokens而不是JObjects的JArray:
这里是一个例子:
string json = "[null, null, \"x\", null, null, null, 0,[],[[\"x\"], null,[0],[\"x\"]]]";
JArray array = JArray.Parse(json);
// Keep first 3 elements, remove the rest
int max = array.Count;
for (int i = 0; i < max - 3; i++)
{
JToken elem = array[3];
array.Remove(elem);
}
json = array.ToString(Newtonsoft.Json.Formatting.None);
Console.WriteLine(json);