我先将对象转换为json,然后将json转换为xml。我需要执行此操作以将某些属性生成为xml属性而不是元素。一切都按预期工作,除了我无法为每个项目生成单独的xml元素。
C#代码:
string json = JsonConvert.SerializeObject(myObj);
XmlDocument xdoc = JsonConvert.DeserializeXmlNode(json, "root");
生成的json:
{
"header": "myheader",
"transaction": {
"date": "2019-09-24",
"items": [
{
"number": "123",
"unit": "EA",
"qty": 6
},
{
"number": "456",
"unit": "CS",
"qty": 4
}
]
}
}
C#类:
public class Item
{
[JsonProperty("@number")]
public string number { get; set; }
[JsonProperty("@unit")]
public string unit { get; set; }
[JsonProperty("@qty")]
public int qty { get; set; }
}
public class Transaction
{
[JsonProperty("@date")]
public string date { get; set; }
public List<Item> items { get; set; }
}
public class Root
{
public string header { get; set; }
public Transaction transaction { get; set; }
}
生成的(不需要的)输出:
<root>
<header>string</header>
<transaction date="string">
<items number="string" unit="string" qty="0"/>
<items number="string" unit="string" qty="0"/>
</transaction>
</root>
预期输出:
<root>
<header>string</header>
<transaction date="string">
<items>
<item number="string" unit="string" qty="0"/>
<item number="string" unit="string" qty="0"/>
</items>
</transaction>
</root>
按照@Abhineet Chaudhary推荐的关于此link的说明进行操作。它按预期工作。
var jObject = JObject.Parse(json);
jObject.SelectToken("transaction").SelectTokens("items").WrapWithObjects("item");
var finalXml = jObject.ToXElement("root", false);
public static class JsonExtensions
{
public static void WrapWithObjects(this IEnumerable<JToken> values, string name)
{
foreach (var value in values.ToList())
{
var newParent = new JObject();
if (value.Parent != null)
value.Replace(newParent);
newParent[name] = value;
}
}
public static XElement ToXElement(this JObject obj, string deserializeRootElementName = null, bool writeArrayAttribute = false)
{
if (obj == null)
return null;
using (var reader = obj.CreateReader())
return JsonExtensions.DeserializeXElement(reader, deserializeRootElementName, writeArrayAttribute);
}
static XElement DeserializeXElement(JsonReader reader, string deserializeRootElementName, bool writeArrayAttribute)
{
var converter = new Newtonsoft.Json.Converters.XmlNodeConverter() { DeserializeRootElementName = deserializeRootElementName, WriteArrayAttribute = writeArrayAttribute };
var jsonSerializer = JsonSerializer.CreateDefault(new JsonSerializerSettings { Converters = new JsonConverter[] { converter } });
return jsonSerializer.Deserialize<XElement>(reader);
}
}