查看bash（1）手册页中的“Array”部分，我没有找到切片数组的方法。
所以我想出了这个过于复杂的功能：
#!/bin/bash
# @brief: slice a bash array
# @arg1: output-name
# @arg2: input-name
# @args: seq args
# ----------------------------------------------
function slice() {
local output=$1
local input=$2
shift 2
local indexes=$(seq $*)
local -i i
local tmp=$(for i in $indexes
do echo "$(eval echo \"\${$input[$i]}\")"
done)
local IFS=$'\n'
eval $output="( \$tmp )"
}
像这样使用：
$ A=( foo bar "a b c" 42 )
$ slice B A 1 2
$ echo "${B[0]}" # bar
$ echo "${B[1]}" # a b c
有一个更好的方法吗？
请参阅Bash Parameter Expansion页面中的man部分。 A[@]返回数组的内容，:1:2从索引1开始获取长度为2的切片。
A=( foo bar "a b c" 42 )
B=("${A[@]:1:2}")
C=("${A[@]:1}") # slice to the end of the array
echo "${B[@]}" # bar a b c
echo "${B[1]}" # a b c
echo "${C[@]}" # bar a b c 42
echo "${C[@]: -2:2}" # a b c 42 # The space before the - is necesssary
注意，保留了“a b c”是一个数组元素（并且它包含额外空间）的事实。
还有一个方便的快捷方式，可以从指定的索引开始获取数组的所有元素。例如，“$ {A [@]：1}”将是数组的“尾部”，即没有第一个元素的数组。
version=4.7.1
A=( ${version//\./ } )
echo "${A[@]}" # 4 7 1
B=( "${A[@]:1}" )
echo "${B[@]}" # 7 1
像Python一样的数组切片（来自rebash库）：
array_slice() {
local __doc__='
Returns a slice of an array (similar to Python).
From the Python documentation:
One way to remember how slices work is to think of the indices as pointing
between elements, with the left edge of the first character numbered 0.
Then the right edge of the last element of an array of length n has
index n, for example:
```
+---+---+---+---+---+---+
| 0 | 1 | 2 | 3 | 4 | 5 |
+---+---+---+---+---+---+
0 1 2 3 4 5 6
-6 -5 -4 -3 -2 -1
```
>>> local a=(0 1 2 3 4 5)
>>> echo $(array.slice 1:-2 "${a[@]}")
1 2 3
>>> local a=(0 1 2 3 4 5)
>>> echo $(array.slice 0:1 "${a[@]}")
0
>>> local a=(0 1 2 3 4 5)
>>> [ -z "$(array.slice 1:1 "${a[@]}")" ] && echo empty
empty
>>> local a=(0 1 2 3 4 5)
>>> [ -z "$(array.slice 2:1 "${a[@]}")" ] && echo empty
empty
>>> local a=(0 1 2 3 4 5)
>>> [ -z "$(array.slice -2:-3 "${a[@]}")" ] && echo empty
empty
>>> [ -z "$(array.slice -2:-2 "${a[@]}")" ] && echo empty
empty
Slice indices have useful defaults; an omitted first index defaults to
zero, an omitted second index defaults to the size of the string being
sliced.
>>> local a=(0 1 2 3 4 5)
>>> # from the beginning to position 2 (excluded)
>>> echo $(array.slice 0:2 "${a[@]}")
>>> echo $(array.slice :2 "${a[@]}")
0 1
0 1
>>> local a=(0 1 2 3 4 5)
>>> # from position 3 (included) to the end
>>> echo $(array.slice 3:"${#a[@]}" "${a[@]}")
>>> echo $(array.slice 3: "${a[@]}")
3 4 5
3 4 5
>>> local a=(0 1 2 3 4 5)
>>> # from the second-last (included) to the end
>>> echo $(array.slice -2:"${#a[@]}" "${a[@]}")
>>> echo $(array.slice -2: "${a[@]}")
4 5
4 5
>>> local a=(0 1 2 3 4 5)
>>> echo $(array.slice -4:-2 "${a[@]}")
2 3
If no range is given, it works like normal array indices.
>>> local a=(0 1 2 3 4 5)
>>> echo $(array.slice -1 "${a[@]}")
5
>>> local a=(0 1 2 3 4 5)
>>> echo $(array.slice -2 "${a[@]}")
4
>>> local a=(0 1 2 3 4 5)
>>> echo $(array.slice 0 "${a[@]}")
0
>>> local a=(0 1 2 3 4 5)
>>> echo $(array.slice 1 "${a[@]}")
1
>>> local a=(0 1 2 3 4 5)
>>> array.slice 6 "${a[@]}"; echo $?
1
>>> local a=(0 1 2 3 4 5)
>>> array.slice -7 "${a[@]}"; echo $?
1
'
local start end array_length length
if [[ $1 == *:* ]]; then
IFS=":"; read -r start end <<<"$1"
shift
array_length="$#"
# defaults
[ -z "$end" ] && end=$array_length
[ -z "$start" ] && start=0
(( start < 0 )) && let "start=(( array_length + start ))"
(( end < 0 )) && let "end=(( array_length + end ))"
else
start="$1"
shift
array_length="$#"
(( start < 0 )) && let "start=(( array_length + start ))"
let "end=(( start + 1 ))"
fi
let "length=(( end - start ))"
(( start < 0 )) && return 1
# check bounds
(( length < 0 )) && return 1
(( start < 0 )) && return 1
(( start >= array_length )) && return 1
# parameters start with $1, so add 1 to $start
let "start=(( start + 1 ))"
echo "${@: $start:$length}"
}
alias array.slice="array_slice"
假设我正在从用户那里读取一个数组，那么我希望看到包含3到7的元素。
cnt=0
while read var;
do
myarr[cnt]=$var
cnt=$((cnt+1))
done
echo ${myarr[@]:3:5}