我已经访问了Removing sublists from a list of lists,但是当我为数据集扩展它时,它对我的情况不起作用。因此发布了一个新问题。
list1=[['A,C,D', 'Y', 'hello'],
['A,B,D', 'Y', 'hello'],
['B,C,D', 'Y', 'hello'],
['A,B,C,D', 'Y', 'hello'],
['A', 'Z', 'hello'],
['A,C', 'Z', 'hello'],
['B,C', 'Z', 'hello'],
['A,C', 'Z', 'hello'],
['A,B,C', 'Z', 'hello'],
['H,I,J,K', 'Z', 'hello'],
['H,K', 'Z', 'hello'],
['H,L', 'Z', 'hello'],
['I,J,K,L', 'Z', 'hello'],
['H,I,J,K,L', 'Z', 'hello'],
['B,C,D','Z','hi'],
['A,D,C,B','Z','hi'],
['E,F,G,H','T','welcome'],
['A,E,H','T','welcome']]
我想删除一些元素并在下面发布所需的输出:
**Output**
[['A,B,C,D', 'Y', 'hello'],
['A,B,C', 'Z', 'hello'],
['H,I,J,K,L', 'Z', 'hello'],
['A,D,C,B','Z','hi'],
['E,F,G,H','T','welcome']]
我尝试使用下面的代码:
sets = [set(l) for l in lists]
new_list = [l for l,s in zip(lists, sets) if not any(s < other for other in sets)]
查看您的输入和所需的输出,似乎您想在","
上拆分每个列表的第一个元素。现在它们是逗号分隔的字符串,因此子集逻辑将不适用于它们。所以你可以做:
sets = [set(l[0].split(',')) | set(l[1:]) for l in lists]