我使用rmp_serde序列化和反序列化某些结构。一个结构包含一个通用类型,编译器说:
error: the trait bound `T: api::_IMPL_SERIALIZE_FOR_User::_serde::Serialize` is not satisfied
label: the trait `api::_IMPL_SERIALIZE_FOR_User::_serde::Serialize` is not implemented for `T`
对于NodeJ,messagepack可以正常工作,但是我正在使用rust几天了...
extern crate rmp_serde as rmps;
use bytes::Bytes;
use serde::{Deserialize, Serialize};
#[derive(Deserialize, Serialize, PartialEq, Debug)]
pub struct User {
pub name: String,
pub token: String,
pub hash: String,
}
#[derive(Deserialize, Serialize, PartialEq, Debug)]
pub struct Message<T> {
pub utc: u64,
pub mtd: u64,
pub user: User,
pub payload: T,
}
pub fn serializeResponseMessage<T>(obj: &Message<T>) -> Vec<u8> {
let serialized = rmps::encode::to_vec_named(&obj).unwrap();
serialized
}
pub fn deserializeUserLoginRequest<T>(msg: &Bytes) -> Message<T> {
// let mut obj = Message {
// utc: 0,
// mtd: 0,
// user: User {
// name: "".to_string(),
// token: "".to_string(),
// hash: "".to_string(),
// },
// payload: User {
// name: "".to_string(),
// token: "".to_string(),
// hash: "".to_string(),
// },
// };
let obj: Message<T> = rmps::decode::from_read_ref(&msg).unwrap();
obj
}
我该如何实现?
您需要使rustc
确信T
确实可以序列化和反序列化:
pub fn serializeResponseMessage<T>(obj: &Message<T>) -> Vec<u8>
where
T: Serialize,
{
rmps::encode::to_vec_named(obj).unwrap()
}
pub fn deserializeUserLoginRequest<'de, T>(msg: &'de Bytes) -> Message<T>
where
T: Deserialize<'de>,
{
rmps::decode::from_read_ref(msg).unwrap()
}