您如何用名称中的冒号来解析JSON？ Android / Java

Question

例如：{ "primary:title":"Little Red Riding Hood"}

我的Java解析器（Android（Android）中总是由于主标题和标题之间的冒号而被卡住。我可以轻松解析其他任何内容，我只需要帮助即可。

public class MainActivity extends Activity {
    /** Called when the activity is first created. */

    TextView txtViewParsedValue;

    private JSONObject jsonObject;
    private JSONArray jsonArray;

    String [] titles, links, mediaDescriptions, mediaCredits, descriptions, dcCreators, pubDates, categories;
    String [] permalinks, texts;            // guid
    String [] rels, hrefs;
    String [] urls, media, heights, widths; // media:content

    String strParsedValue = "";

    private String strJSONValue;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        strJSONValue = readRawTextFile(this, R.raw.jsonextract);

        txtViewParsedValue = (TextView) findViewById(R.id.text_view_1);

        try {
            parseJSON();

        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }

    public void parseJSON() throws JSONException
    {
        txtViewParsedValue.setText("Parse 1");

        jsonObject = new JSONObject(strJSONValue);
        jsonArray = jsonObject.getJSONArray("item");

        titles = new String[jsonArray.length()];
        links = new String[jsonArray.length()];
        permalinks = new String[jsonArray.length()];
        texts = new String[jsonArray.length()];
        mediaDescriptions = new String[jsonArray.length()];
        mediaCredits = new String[jsonArray.length()];
        descriptions = new String[jsonArray.length()];
        dcCreators = new String[jsonArray.length()];
        pubDates = new String[jsonArray.length()];
        categories = new String[jsonArray.length()];

        txtViewParsedValue.setText("Parse 2");

        for (int i=0; i<jsonArray.length(); i++)
        {
            JSONObject object = jsonArray.getJSONObject(i);

            titles[i] = object.getString("title");
            links[i] = object.getString("link");

            JSONObject guidObj = object.getJSONObject("guid");
            permalinks[i] = guidObj.getString("isPermaLink");
            texts[i] = guidObj.getString("text");
            //mediaDescriptions[i] = object.getString("media:description");
            //mediaCredits[i] = object.getString("media:credit");

                // *** THE PARSER FAILS IF THE COMMENTED LINES ARE IMPLEMENTED BECAUSE
                // OF THE : IN BETWEEN THE NAMES ***

            descriptions[i] = object.getString("description");
            //dcCreators[i] = object.getString("dc:creator");
            pubDates[i] = object.getString("pubDate");
            categories[i] = object.getString("category");   
        }



        for (int i=0; i<jsonArray.length(); i++)
        {
            strParsedValue += "\nTitle: " + titles[i];
            strParsedValue += "\nLink: " + links[i];
            strParsedValue += "\nPermalink: " + permalinks[i];
            strParsedValue += "\nText: " + texts[i];
            strParsedValue += "\nMedia Description: " + mediaDescriptions[i];
            strParsedValue += "\nMedia Credit: " + mediaCredits[i];
            strParsedValue += "\nDescription: " + descriptions[i];
            strParsedValue += "\nDC Creator: " + dcCreators[i];
            strParsedValue += "\nPublication Date: " + pubDates[i];
            strParsedValue += "\nCategory: " + categories[i];
            strParsedValue += "\n";
        }


        txtViewParsedValue.setText(strParsedValue);
    }

    public static String readRawTextFile(Context ctx, int resId)
    {
         InputStream inputStream = ctx.getResources().openRawResource(resId);

            InputStreamReader inputreader = new InputStreamReader(inputStream);
            BufferedReader buffreader = new BufferedReader(inputreader);
             String line;
             StringBuilder text = new StringBuilder();

             try {
               while (( line = buffreader.readLine()) != null) {
                   text.append(line);
                   //text.append('\n');
                 }
           } catch (IOException e) {
               return null;
           }
             return text.toString();
    }

Answer 1

首先，为了回答您的问题，JSONObject和org.json。*类解析键中带有冒号的键（如果格式正确）没有问题。通过了以下单元测试，这意味着它能够解析您的示例方案：

public void testParsingKeysWithColons() throws JSONException {
    String raw = "{ \"primary:title\":\"Little Red Riding Hood\"}";
    JSONObject obj = new JSONObject(raw);
    String primaryTitle = obj.getString("primary:title");
    assertEquals("Little Red Riding Hood", primaryTitle);
}

[另一建议是为数据使用字符串数组很笨拙，并且使用数据结构来表示对象会更好地组织您的数据。代替标题，链接，描述的字符串数组；使用具有这些属性的对象并列出对象。例如：

public class MyDataStructure {

    public String title;
    public String primaryTitle;
    public String link;
    public String mediaDescription;

    public static class Keys {
        public static String title = "title";
        public static String primaryTitle = "primary:title";
        public static String link = "link";
        public static String mediaDescription = "media:description";
    }

}

然后，您可以创建一个“ translator”类，该类为您完成所有解析并返回对象列表。这更容易使用和跟踪。您无需考虑数据错位或其中一个阵列中的数据多于或少于预期的情况。您还可以更轻松地进行时间测试，问题出在哪里，如果您的输入数据丢失了任何内容，或者您​​的json格式有误。

public class MyDataStructureTranslator {

    public static List<MyDataStructure> parseJson(String rawJsonData) throws JSONException {

        List<MyDataStructure> list = new ArrayList<MyDataStructure>();
        JSONObject obj = new JSONObject(rawJsonData);
        JSONArray arr = obj.getJSONArray("item");

        for(int i = 0; i < arr.length(); i++) {
            JSONObject current = arr.getJSONObject(i);
            MyDataStructure item = new MyDataStructure();
            item.title = current.getString(MyDataStructure.Keys.title);
            item.primaryTitle = current.getString(MyDataStructure.Keys.primaryTitle);
            item.link = current.getString(MyDataStructure.Keys.link);
            item.mediaDescription = current.getString(MyDataStructure.Keys.mediaDescription);
            list.add(item);
        }

        return list;
    }

}

Answer 2

由于C＃标识符不能包含冒号，所以只需指定一个json属性名称即可，该名称映射到确切的json名称，例如：

[JsonProperty("primary:title")]
public string PrimaryTitle{ get; set; }