在一列与另一列的值完全相同的情况下，按此排序。

Question

我需要在一列与另一列的值完全相同的地方进行排序。有什么方法可以做到这一点吗？如果有，请告诉我。ORDER BY wordMatch = wordCount

SELECT * , 
( input LIKE  '% i %') + 
( input LIKE  '% love %' ) + 
( input LIKE  '% you %' ) AS wordMatch, 
( LENGTH( input ) - LENGTH( REPLACE( input,  ' ',  '' ) ) -1 ) AS wordCount
FROM allData
HAVING wordMatch > ( wordCount * 0.6666 ) 
AND wordCount > ( 3 * 0.6666 ) 
ORDER BY wordMatch = wordCount
LIMIT 50

Answer 1

如果你想先让最接近的匹配，那么使用 desc:

order by (wordMatch = wordCount) desc

或者，你也可能想要差值的绝对值。

order by abs(wordMatch - wordCount)

Answer 2

我在找这样的东西。

ORDER BY wordMatch = wordCount DESC , wordCount DESC