我编程太阳系。 ATM所有行星都与太阳相互作用(万有引力)。现在我也希望每个行星都与所有其他行星相互作用(实际上是怎样)。我以为我可以用双循环来做到这一点。我尝试了但它没有用。你可以帮帮我吗?我认为错误与太阳有关,行星有一个固定点。但现在它始终是地球的行星。但我真的不知道......这是我的代码:
from vpython import *
#Konstanten zum rechnen
s_rad0 = 6.9e8
s_rad1 = 30 * s_rad0
e_rad = s_rad1 * 0.9
m_rad = e_rad * 0.4
ae = 200 * s_rad0 #1 Astr. Einheit bezieht sich auf Ent. Sonne-Erde
ae2 = 200 * s_rad0 #bezieht sich auf Ent. Sonne-Mond
g = 6.6725e-11
framerate = 100
#array liste von Planeten
planets = []
class Sphere(object):
def __init__(self, pos, radius, make_trail):
self.pos = pos
self.radius = radius
self.make_trail = make_trail
class planet(Sphere):
def __init__(self, pos, radius, make_trail, mass, velocity):
super().__init__(pos, radius, make_trail)
self.mass = mass
self.velocity = velocity
planetSphere = sphere (pos = self.pos, radius = self.radius, make_trail = self.make_trail, mass = self.mass, velocity = self.velocity)
sun = planet(pos=vec(0,0,0),radius=s_rad1*1.5, make_trail=True, mass=2e30, velocity=vec(0,0,0))
mercury = planet(pos=vec(ae/3,0,0), radius=s_rad1/1.5, make_trail=True, mass=3.25e23, velocity=vec(0,0,-47000))
venus = planet(pos=vec(ae/1.6,0,0), radius=s_rad1/1.3, make_trail=True, mass=4.9e24, velocity=vec(0,0,-35000))
earth = planet(pos=vec(ae,0,0), radius=e_rad, mass=5.9e24, make_trail=True, velocity=vec(0,0,-25000))
mars = planet(pos=vec(ae*1.52,0,0), radius=s_rad1/1.8, make_trail=True, mass=6.4e23, velocity=vec(0,0,-24000))
jupiter = planet(pos=vec(ae*5.18,0,0), radius=s_rad1/1.2, make_trail=True, mass=10e27, velocity=vec(0,0,-9678))
saturn = planet(pos=vec(ae*9.5,0,0), radius=s_rad1/1.4, make_trail=True, mass=5.7e26, velocity=vec(0,0,-7678))
uranus = planet(pos=vec(ae*19.13,0,0), radius=s_rad1/1.7, make_trail=True, mass=8.7e25, velocity=vec(0,0,-6772))
neptun = planet(pos=vec(ae*30,0,0), radius=s_rad1/1.7, make_trail=True, mass=1.02e26, velocity=vec(0,0,-5344))
pluto = planet(pos=vec(ae*39.37,0,0), radius=s_rad1/2.4, make_trail=True, mass=1.3e22, velocity=vec(0,0,-4740))
planets.extend((mercury,venus,earth,mars,jupiter,saturn,uranus,neptun,pluto))
dt = 10000
time = 0.1
while (True):
rate(framerate)
#for-Schlaufe für Berechnung jedes einzelnen Planeten
g_forceS = vec(0,0,0)
for planet in planets:
g_force = g * sun.mass * planet.mass * (sun.pos - planet.pos).norm() / (sun.pos - planet.pos).mag2
for planet in planets:
g_force = g * planet.mass * planet.mass * (planet.pos - planet.pos).norm() / (planet.pos - planet.pos).mag2
#Sonne
g_forceS -= g_force
#print(sun.pos)
#Änderung des Velocity Vektor wird zum alten addiert
#Da a=F/m // V = a*t(a*dt) 2 Geschw. vektoriell durch F/m ausgedrückt.
planet.velocity = planet.velocity + ( g_force / planet.mass) * dt #Richtungsänderung
#Diese Änderung wird zur alten Position addiert = neue Position
planet.pos += planet.velocity * dt
sun.velocity = sun.velocity + ( g_forceS / sun.mass) * dt #Richtungsänderung
sun.pos += sun.velocity * dt
你问题中的缩进都搞砸了,但是看起来你看起来像是在做错了。
for planet in planets:
g_force = g * sun.mass * planet.mass * (sun.pos - planet.pos).norm() / (sun.pos - planet.pos).mag2
for planet in planets:
g_force = g * planet.mass * planet.mass * (planet.pos - planet.pos).norm() / (planet.pos - planet.pos).mag2
g_forceS -= g_force
这里有几个错误。你应该逐步完成自己的代码,看看是什么。添加打印语句有助于理解。但要注意两件事。一:内循环中的变量名与外循环中的变量相同。外循环每次设置planet
(即9次),然后内循环覆盖它。您需要将一个主体和另一个主体的概念保持在单独的变量中。二:你只在内循环运行后更新一次g_forceS
,所以这只是使用planet
的最新值而不是更新9次更新。
重写您的代码以具有此结构:
for body in bodies: # Update each of the bodies in turn.
force = np.zeros(3) # We need to work out the force on the body.
for other_body in bodies: # The force is the result of all the other bodies.
if other_body is not body: # The main body doesn't count as another body.
force += gravity(body, other_body)
body.update(force) # Update the body according to the force on it.
我现在有这个解决方案和它的工作
dt = 10000
time = 0.1
while (True):
rate(framerate)
for planet in planets:
g_force = vec(0,0,0)
for planet1 in planets:
if planet != planet1:
g_force += g * planet1.mass * planet.mass * (planet1.pos - planet.pos).norm() / (planet1.pos - planet.pos).mag2
#print((sun.pos - planet.pos).mag2)
#Änderung des Velocity Vektor wird zum alten addiert
#Da a=F/m // V = a*t(a*dt) 2 Geschw. vektoriell durch F/m ausgedrückt.
planet.velocity = planet.velocity + ( (g_force) / planet.mass) * dt
#Diese Änderung wird zur alten Position addiert = neue Position
planet.pos += planet.velocity * dt