Hibernate - 映射：无法确定＃的类型，在表中：＃，对于列：＃

Question

我尝试了一切，但我被卡住了。你能帮我吗？

这个小项目只是对大型数据库的初步测试。我只使用Hibernate一个星期，我试图将它与Srping MVC Tomcat连接起来。

但现在我只想识别映射中的错误。

安慰：

    `Initial SessionFactory creation failed.org.hibernate.MappingException: Could not determine type for: hiber.data_examplecompany.Address, at table: EMPLOYEE, for columns: [org.hibernate.mapping.Column(address)]
Exception in thread "main" java.lang.ExceptionInInitializerError
    at tools.hiber.HiberUtil.<clinit>(HiberUtil.java:19)
    at tools.hiber.HiberSave.main(HiberSave.java:15)
Caused by: org.hibernate.MappingException: Could not determine type for: hiber.data_examplecompany.Address, at table: EMPLOYEE, for columns: [org.hibernate.mapping.Column(address)]
    at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:486)
    at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:453)
    at org.hibernate.mapping.Property.isValid(Property.java:226)
    at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:624)
    at org.hibernate.mapping.RootClass.validate(RootClass.java:267)
    at org.hibernate.boot.internal.MetadataImpl.validate(MetadataImpl.java:347)
    at org.hibernate.boot.internal.SessionFactoryBuilderImpl.build(SessionFactoryBuilderImpl.java:466)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:708)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:724)
    at tools.hiber.HiberUtil.<clinit>(HiberUtil.java:15)
    ... 1 more

employee.Java:

package hiber.data_examplecompany;

import javax.persistence.Access;
import javax.persistence.AccessType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.OneToOne;
import javax.persistence.Table;

import org.hibernate.annotations.Cascade;

@Entity
@Table(name = "EMPLOYEE")
@Access(value=AccessType.FIELD)
public class Employee {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "emp_id")
    private long id;
    @Column(name = "emp_name")
    private String name;
    @Column(name = "emp_salary")
    private double salary;

    private Address address;

    public long getId() {
        return id;
    }

    public void setId(long id) {
        this.id = id;
    }

    @OneToOne(mappedBy = "employee")
    @Cascade(value = org.hibernate.annotations.CascadeType.ALL)
    public Address getAddress() {
        return address;
    }

    public void setAddress(Address address) {
        this.address = address;
    }

    @Column(name = "emp_name")
    public String getName() {
        System.out.println("Employee getName called");
        return name;
    }

    public void setName(String name) {
        System.out.println("Employee setName called");
        this.name = name;
    }

    @Column(name = "emp_salary")
    public double getSalary() {
        return salary;
    }

    public void setSalary(double salary) {
        this.salary = salary;
    }

    @Override
    public String toString() {
        return "Id= " + id + ", Name= " + name + ", Salary= " + salary
                + ", {Address= " + address + "}";
    }

}

address.Java:

package hiber.data_examplecompany;

import javax.persistence.Access;
import javax.persistence.AccessType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.OneToOne;
import javax.persistence.PrimaryKeyJoinColumn;
import javax.persistence.Table;

import org.hibernate.annotations.GenericGenerator;
import org.hibernate.annotations.Parameter;

@Entity
@Table(name = "ADDRESS")
@Access(value=AccessType.FIELD)
public class Address {

    @Id
    @Column(name = "emp_id", unique = true, nullable = false)
    @GeneratedValue(generator = "gen")
    @GenericGenerator(name = "gen", strategy = "foreign", parameters = { @Parameter(name = "property", value = "employee") })
    private long id;

    @Column(name = "address_line1")
    private String addressLine1;

    @Column(name = "zipcode")
    private String zipcode;

    @Column(name = "city")
    private String city;

    @OneToOne
    @PrimaryKeyJoinColumn
    private Employee employee;

    public long getId() {
        return id;
    }

    public void setId(long id) {
        this.id = id;
    }

    public String getAddressLine1() {
        return addressLine1;
    }

    public void setAddressLine1(String addressLine1) {
        this.addressLine1 = addressLine1;
    }

    public String getZipcode() {
        return zipcode;
    }

    public void setZipcode(String zipcode) {
        this.zipcode = zipcode;
    }

    public String getCity() {
        return city;
    }

    public void setCity(String city) {
        this.city = city;
    }

    public Employee getEmployee() {
        return employee;
    }

    public void setEmployee(Employee employee) {
        this.employee = employee;
    }

    @Override
    public String toString() {
        return "AddressLine1= " + addressLine1 + ", City=" + city
                + ", Zipcode=" + zipcode;
    }
}

感谢您投入的时间！ :)

Answer 1

实际上，你的映射是可以的。每个员工都可以拥有一个地址。但我认为你做了一个小错误。据我所知每当使用注释在hibernate中创建表时，在一个地方使用所有注释我指的是Field或属性级别。基本上，Hibernate将根据@Id注释位置查看其他所需的注释。所以在你的情况下@Id在字段级别，而@OneToOne在Employee表的属性级别。请做同样的更改，然后再试一次，让我知道。

@Entity
@Table(name = "EMPLOYEE")
@Access(value=AccessType.FIELD)
public class Employee {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "emp_id")
    private long id;
    @Column(name = "emp_name")
    private String name;
    @Column(name = "emp_salary")
    private double salary;

     @OneToOne(mappedBy = "employee" , cascade = CascadeType.ALL)   
    private Address address;

    public long getId() {
        return id;
    }

    public void setId(long id) {
        this.id = id;
    }


    public Address getAddress() {
        return address;
    }

    public void setAddress(Address address) {
        this.address = address;
    }


    public String getName() {
        System.out.println("Employee getName called");
        return name;
    }

    public void setName(String name) {
        System.out.println("Employee setName called");
        this.name = name;
    }


    public double getSalary() {
        return salary;
    }

    public void setSalary(double salary) {
        this.salary = salary;
    }

    @Override
    public String toString() {
        return "Id= " + id + ", Name= " + name + ", Salary= " + salary
                + ", {Address= " + address + "}";
    }