尝试编译代码时出现以下错误：
LNK1169：找到一个或多个多重定义的符号 LNK2005: [函数名称] 已在 main.obj 中定义 ^^^ 每个函数都会出现错误 LNK2005
这是我当前的代码： 主.c
#define _CRT_SECURE_NO_WARNINGS –
#pragma once
#include "pa-1.h"
#include "pa-1.c"
int main()
{
//Declaring an array
int list[3] = {0,0,0};
//Declaring variables
int n = 0;
int x = 0;
int r = 0;
int y = 0;
int z = 0;
int rotateNum = 0;
int searchRecur = 0;
int collatzNum = 0;
int average = 0;
bool results;
char brackets = "";
char lookFor = "";
char paragraph = "";
char fString = "";
char sString = "";
char *e = "";
char *pattern = "";
char *text = "";
char *s1 = "";
char *s2 = "";
char *s3 = "";
//Function 1
//Will see if input is an armstrong number
printf("Enter a number and the program will check to see if it's an armstrong number: ");
scanf("%d", n);
results = f_armstrong(n);
if (results == true)
{
printf(" is an armstrong number");
}
else
{
printf("%d is not an armstrong number", n);
}
/*
//Function 2
//Will see if brackets are balanced
printf("Enter brackets and the program will check to see if they are in order: ");
scanf("%s", brackets);
*e = brackets;
results = f_brackets(*e);
if (results == true)
{
printf("Your brackets are in order");
}
else
{
printf("Your brackets are not in order");
}
//Function 3
//Will see if input is a perfect number
printf("Enter a number and the program will check to see if it's a perfect number: ");
scanf("%d", x);
results = f_perfect(x);
if (results == true)
{
printf("%d is a perfect number", x);
}
else
{
printf("%d is not a perfect number", x);
}
//Funtction 4
//Will rotate input by a number that is also given
printf("Enter a number that you want to rotate its digits: ");
scanf("%d", n);
printf("Enter a number that you want to rotate by: ");
scanf("%d", r);
rotateNum = f_rotate(n, r);
printf("The new number is: %d", rotateNum);
//Funtction 5
//Will search for a pattern in a text
printf("Enter a text you want to search through: ");
scanf("%s", paragraph);
printf("Enter a pattern you want to search for: ");
scanf("%s", lookFor);
*text = paragraph;
*pattern = lookFor;
searchRecur = f_str_search(*pattern, *text);
printf("%s can be found in your text %D times", *pattern, searchRecur);
//Funtction 6
//Will perform the Collatz conjucture on input
printf("Enter a number for the program to perform the Collatz conjucture to: ");
scanf("%d", n);
collatzNum = f_collatz_count(n);
printf("It took %d iterations", collatzNum);
//Funtction 7
//This function will take a number and create an array with the amount and perform other operation
printf("Enter a number to determine how many random numbers are generated: ");
scanf("%d", n);
average = f_array(n);
printf("The numbers were randomly generated between 1-99 and multiplied by 2. The following number is the average of the (up to 5) numbers divisible by 3: %d", average);
//Funtction 8
//This function will take two strings and put them into one, in shorter/larger/shorter order
printf("Enter the first text you want to forge with: ");
scanf("%s", fString);
printf("Enter the second text you want to forge with: ");
scanf("%s", sString);
*s1 = fString;
*s2 = sString;
f_strings(*s1, *s2, *s3);
printf("Your new string is: %s", *s3);
//Function 9
//This will take three numbers and sort them in order
printf("The program will now take three numbers and sort them in assending order. Enter the first number: ");
scanf("%d", x);
printf("Enter the second number: ");
scanf("%d", y);
printf("Enter the third number: ");
scanf("%d", z);
f_sort(x, y, z, *list);
printf("The numbers in order are: %d %d %d",list[0], list[1], list[2]);
//Funtction 10
//This will look for a set of numbers that equate to the input, when cubed
printf("Enter a number and the program will see if a set of numbers cubed will equate to it: ");
scanf("%d", n);
int * twoValues = f_cubed_sum(n);
if (twoValues[0] != NULL)
{
printf("The two values are: %d and %d", twoValues[0], twoValues[1]);
}
else
{
printf("There is no pair of integers that satasfy the formula");
}
free(twoValues);
*/
return 0;
}
pa-1.c：
#pragma once
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
#include "pa-1.h"
/*
This function takes an integer n as a parameter.
The purpose of this function is to determine if n is an
"Armstrong Number".
*/
bool f_armstrong(int n)
{
int numLength; //Holds how many digits are in n
int finalSum = 0; //Holds the final test value to compare with n
int digits = 0; //Holds the value of parameter n
int remainder; //Holds the value of the remainder
int userNum = n; //Holds the value of n
// Count number of digits in n
while (userNum != 0)
{
digits++;
//Takes away a digit from n
userNum /= 10;
}
//Re-assign the variables
numLength = digits;
userNum = n;
//Test loop to determine if it's an Armstrong number
while (userNum != 0)
{
//Find digit in the number
remainder = userNum % 10;
//Exponential increase the digit and add it to the sum
finalSum += pow(remainder, digits);
userNum /= 10;
}
//If the test was true
if (finalSum == n)
{
return true;
}
//If the test fails
else
{
return false;
}
}
/*
THe user enters a string phrase into the function.
The function will then go through the string and count the
number of open and closed brackets. If the sizes match it
returns true, if not it returns false.
*/
bool f_brackets(char *e)
{
//Declaring variables
int brackLen;
int counter = 0;
int openCount = 0;
int closeCount = 0;
char curChar, brackets;
bool results = true;
brackets = *e;
//Getting the length of the string
brackLen = strlen(e);
while (counter < brackLen && results == true)
{
curChar = getchar(brackets);
if (curChar == '[')
{
openCount = openCount + 1;
}
else
{
closeCount = closeCount + 1;
}
if (closeCount > openCount)
{
results = false;
}
counter = counter + 1;
}
return results;
}
/*
The user will enter a number theu want to test.
The function will then add up the sum of the divisors.
If the sum and number match it returns true, if not it
returns true.
*/
bool f_perfect(int x)
{
int userNum = x; //Variable to hold the parameter value
int sum = 1; //Holds the final sum of perfect numbers
//Divided by the user's number
//Starts at 2 since all numbers are divisable by 1
int divisor = 2;
//While the user's number is greater then the divisor
while (divisor < userNum)
{
//Int to hold the value
int test = userNum % divisor;
//If test is 0, then userNum is divisable
if (test == 0)
{
//Add the divisable to the overall sum
sum += divisor;
}
//Incrememnt
divisor++;
}
//If the sum of divisors is equal to the user's number
if (userNum == sum)
{
return true;
}
//If the sum of divisors is not equal to the user's number
else
{
return false;
}
}
/*
The purpose of this function is for the user to enter a number,
and then they enter another number which the function uses to rotate
the values of their first number.
*/
int f_rotate(int n, int r)
{
int number = n; //Holds the value of users number
const int mod = 10; //Constant value used for modulus command
int rotater = r; //Value to hold how many rotations user wants
int multiplier = 10; //Variable that will be used for multiplications
int digits = 0; //Variable to hold how many values are in number
int finalNum = 0; //Variable that holds the final rotated number
//For loop to determine how many numbers are in users entered value
for (int i = 0; number > 0; i++)
{
//Remove a digit from the value and increment
number /= 10;
digits++;
}
//Loop that will increment multiplier by 10 until it has the same 0's as user number
for (int i = 1; i < digits - rotater; i++)
{
multiplier *= 10;
}
//Reset number to original value
number = n;
//Loop until it's been rotated the correct amount of times
for (int i = 0; i < rotater; i++)
{
//Temp value that will hold the value of a spot in the user's number
int temp;
//Mod 10 to get the digit by itself
temp = number % 10;
//Subtract the value from the number and get rid of a 0
number -= temp;
number /= 10;
//If the digit did not equal 0
if (temp != 0)
{
//Multiply the the value by the multiplier and add it to final num
finalNum += temp * multiplier;
multiplier *= 10;
}
}
//Add the numbers not being rotated to the final number
finalNum += number;
//Return the rotated number
return finalNum;
}
/*
The user enters a pattern that they would like to search for.
The user also enters a text that they want to check for patterns.
The function will return the amount of times it finds the pattern
in the test.
*/
int f_str_search(char *pattern, char *text)
{
int patSize = strlen(pattern); //Varaible to hold size of pattern
int textSize = strlen(text); //Varaible to hold size of text
int occurence = 0; //Variable to hold amount of times the pattern is matched
int patElement = 0; //Array element for pattern
int textElem = 0; //Array element for text
int match = 0; //Variable to hold how many matched elements are found
//While there's still chars left to test in the text string
while (textElem < textSize)
{
//If the values in the element match
if (*(pattern + patElement) == *(text + textElem))
{
//Increment match and the pattern element
match++;
patElement++;
}
//If the values in the element do not match
else
{
//Reset match and go back to the first char in pattern
match = 0;
patElement = 0;;
}
//If matches equal size of pattern, pattern is found
if (match == patSize)
{
//Reset match and pattern element to continue checking
match = 0;
patElement = 0;
//Increment the occurence
occurence++;
//Decrement text element to start checking again in last element a match was found
textElem--;
}
//
textElem++;
}
return occurence;
}
/*
The user enters a natural number.
The program will use the "The Collatz Conjecture" and return
the amount of iterations it took to get the user's number to
equal 1.
*/
int f_collatz_count(int n)
{
int userNum = n; //Variable to hold the user's number
int iteration = 0; //Variable to hold amount of iterations
//While userNum is not 1
while (userNum != 1)
{
//testNum will hold the remainder of the number divided by 2
int testNum = userNum % 2;
//If the number was divisable by 2 (even)
if (testNum == 0)
{
//Divide number by 2 and increment iteration
userNum /= 2;
iteration++;
}
//If the number was not divisable by 2 (odd)
else
{
//Multiply the number by 3 and add 1.
userNum = (userNum * 3) + 1;
//Increment iterations
iteration++;
}
}
//Return total iterations
return iteration;
}
/*
User enters a number.
The function will add however many random numbers the user entered.
It will then multiply all the random numbers by 2, and will return the
average of the first 5 numbers divisable by 3.
*/
int f_array(int n)
{
//Creating variables
int remainder, average;
int counter = 0;
int avgCount = 0;
int total = 0;
bool results = false;
//Creating arrayAn
int* A;
A = malloc(n * sizeof(int));
//Initializing random seed
srand(time(NULL));
//Populating array with random numbers
while (counter < n)
{
A[counter] = rand() % 99 + 1;
counter = counter + 1;
}
//Resetting counter
counter = 0;
//Multiplying array by 2
while (counter < n)
{
A[counter] = A[counter] * 2;
counter = counter + 1;
}
//Restting counter
counter = 0;
//Getting the average of first 5 numbers divisible by 3
while (counter < n && results == false)
{
//Checking if divisible by 3
remainder = A[counter] % 3;
if (remainder == 0)
{
total = total + A[counter];
avgCount = avgCount + 1;
}
if (avgCount = 5)
{
results = true;
}
counter = counter + 1;
}
average = total / avgCount;
free(A);
return average;
}
/*
The user enters two different strings.
The function will test to see which one is larger and then return a
combined string with the shorter string, the longer string, and the
shorter string again.
*/
void f_strings(char *s1, char *s2, char *s3)
{
//Declaring variables
int firstCount, secCount;
//Comparing the string lengths
firstCount = strlen(s1);
secCount = strlen(s2);
if (firstCount > secCount)
{
*s3 = *s1 << *s2 << *s1;
}
else
{
*s3 = *s2 << *s1 << *s2;
}
return;
}
/*
The user enters 3 numbers.
The function then sorts those numbers and lists them in ascending
order.
*/
void f_sort(int x, int y, int z, int *list)
{
const int arraySize = 3; //Constant for the size of array
int element = 0; //Holds numerical value for array element
int num1 = x; //Holds value of first entered number
int num2 = y; //Holds value of second entered number
int num3 = z; //Holds value of third entered number
int temp; //Holds value of number being swapped
//If the first number is larger then the second
if (num1 > num2)
{
//Swap their values
temp = num2;
num2 = num1;
num1 = temp;
}
//If the first number is larger then the third
if (num1 > num3)
{
//Swap their values
temp = num3;
num3 = num1;
num1 = temp;
}
//If the second number is larger then the third
if (num2 > num3)
{
//Swap their values
temp = num3;
num3 = num2;
num2 = temp;
}
//Allocate memory
list = (int *)malloc(arraySize);
//Add the values into the array in ascending order
*(list + element) = num1;
element++;
*(list + element) = num2;
element++;
*(list + element) = num3;
printf("%s \n", "Here is your numbers sorted in ascending order:");
//Loops until all 3 values are printed
for (int i = 0; i < arraySize; i++)
{
printf("%d \n", *(list + i));
}
}
/*
The user enters a number.
The function will test if the cubed sum of 2 numbers is equal
to the number they entered.
*/
int *f_cubed_sum(int n)
{
//Variable to hold the max value the program can go to
const int maxValue = cbrt(n);
const int exponant = 3; //Constant exponant value
int element = 0; //Holds value of array
int test1 = 0; //Value of first number cubed
int test2 = 0; //Value of second number cubed
int *pair1;
int *pair2;
int *pairs;
int totalPairs = 0; //Holds if pairs have been found
pair1 = (int *)malloc(5 * maxValue);
pair2 = (int *)malloc(5 * maxValue);
//While the first test number is less then or equal to max value
while (test1 <= maxValue)
{
//Reset second test number to 0
test2 = 0;
//While the second test number is less then or equal to max value
while (test2 <= maxValue)
{
//Sum of the two test numbers
int sum = 0;
//Cube the test numbers and add them to sum
sum += pow(test1, exponant);
sum += pow(test2, exponant);
//If sum is equal to users number
if (sum == n)
{
//If one of the test numbers is 0
if (test1 == 0)
{
*(pair1 + element) = 0;
*(pair2 + element) = test2;
totalPairs += 2;
}
else if (test2 == 0)
{
*(pair1 + element) = test1;
*(pair2 + element) = 0;
totalPairs += 2;
}
else
{
*(pair1 + element) = test1;
*(pair2 + element) = test2;
element++;
totalPairs += 2;
}
}
//Increment test number 2
test2++;
}
//Increment test number 1
test1++;
}
//If no pairs were found
if (totalPairs == 0)
{
//Free memory and return NULL
free(pair1);
free(pair2);
return NULL;
}
//If there were pairs found
else
{
int pairElement = 0;
int pairsElement = 0;
pairs = (int *)malloc(100 * totalPairs);
for (int i = 0; pairElement < sizeof(pair1); i++)
{
if (*(pair2 + pairElement) != 0 && *(pair1 + pairElement) != 0)
{
*(pairs + pairsElement) = *(pair1 + pairElement);
pairsElement++;
*(pairs + pairsElement) = *(pair2 + pairElement);
pairsElement++;
pairElement++;
}
else
{
pairElement++;
}
}
//Return array of pairs
return pairs;
}
}
pa-1.h
#pragma once
// define a boolean type to use in the functions
#ifndef _BOOL_TYPE_
#define _BOOL_TYPE_
typedef enum { false, true } bool;
#endif
bool f_armstrong(int n);
bool f_brackets(char *e);
bool f_perfect(int x);
int f_rotate(int n, int r);
int f_str_search(char *pattern, char *text);
int f_collatz_count(int n);
int f_array(int n);
void f_strings(char *s1, char *s2, char *s3);
void f_sort(int x, int y, int z, int *list);
int *f_cubed_sum(int n);
我正在使用 Visual Studio。
谢谢！
您不应包含
.c#include "pa-1.c"
并编译所有
.cgcc main.c pa-1.c -o prog.exe
编辑：没有注意到您正在使用 Visual Studio，在这种情况下，只需将所有文件添加到同一项目中并构建它就足够了。所以忽略上面的
gcc编写一个 C 程序，允许输入数字列表并使用数组确定所有偶数的总数。