PHP GuzzleHttp。如何使用params发布帖子请求？

Question

如何使用GuzzleHttp（5.0版）发布帖子请求。

我正在尝试执行以下操作：

$client = new \GuzzleHttp\Client();
$client->post(
    'http://www.example.com/user/create',
    array(
        'email' => '[email protected]',
        'name' => 'Test user',
        'password' => 'testpassword'
    )
);

但是我收到了错误：

PHP致命错误：未捕获异常'InvalidArgumentException'，并显示消息'无方法可以处理电子邮件配置密钥'

Answer 1

编辑：此方法现已在6.0中弃用。而不是'身体'使用'form_params'

试试这个

$client = new \GuzzleHttp\Client();
$client->post(
    'http://www.example.com/user/create',
    array(
        'body' => array(
            'email' => '[email protected]',
            'name' => 'Test user',
            'password' => 'testpassword'
        )
    )
);

Answer 2

由于Marco的答案已被弃用，您必须使用以下语法（根据jasonlfunk的评论）：

$client = new \GuzzleHttp\Client();
$response = $client->request('POST', 'http://www.example.com/user/create', [
    'form_params' => [
        'email' => '[email protected]',
        'name' => 'Test user',
        'password' => 'testpassword',
    ]
]);

Request with POST files

$response = $client->request('POST', 'http://www.example.com/files/post', [
    'multipart' => [
        [
            'name'     => 'file_name',
            'contents' => fopen('/path/to/file', 'r')
        ],
        [
            'name'     => 'csv_header',
            'contents' => 'First Name, Last Name, Username',
            'filename' => 'csv_header.csv'
        ]
    ]
]);

REST verbs usage with params

// PUT
$client->put('http://www.example.com/user/4', [
    'body' => [
        'email' => '[email protected]',
        'name' => 'Test user',
        'password' => 'testpassword',
    ],
    'timeout' => 5
]);

// DELETE
$client->delete('http://www.example.com/user');

Async POST data

对于长服务器操作很有用。

$client = new \GuzzleHttp\Client();
$promise = $client->requestAsync('POST', 'http://www.example.com/user/create', [
    'form_params' => [
        'email' => '[email protected]',
        'name' => 'Test user',
        'password' => 'testpassword',
    ]
]);
$promise->then(
    function (ResponseInterface $res) {
        echo $res->getStatusCode() . "\n";
    },
    function (RequestException $e) {
        echo $e->getMessage() . "\n";
        echo $e->getRequest()->getMethod();
    }
);

More information for debugging

如果您想了解更多详细信息，可以使用debug选项，如下所示：

$client = new \GuzzleHttp\Client();
$response = $client->request('POST', 'http://www.example.com/user/create', [
    'form_params' => [
        'email' => '[email protected]',
        'name' => 'Test user',
        'password' => 'testpassword',
    ],
    // If you want more informations during request
    'debug' => true
]);

qazxsw poi对新的可能性更加明确。

Answer 3

注意在Guzzle V6.0 +中，获取以下错误的另一个来源可能是错误地使用JSON作为数组：

传递“body”请求选项作为发送POST请求的数组已被弃用。请使用“form_params”请求选项发送application / x-www-form-urlencoded请求，或使用“multipart”请求选项发送multipart / form-data请求。

不正确：

Documentation

正确：

$response = $client->post('http://example.com/api', [
    'body' => [
        'name' => 'Example name',
    ]
])

正确：

$response = $client->post('http://example.com/api', [
    'json' => [
        'name' => 'Example name',
    ]
])

Answer 4

$response = $client->post('http://example.com/api', [
    'headers' => ['Content-Type' => 'application/json'],
    'body' => json_encode([
        'name' => 'Example name',
    ])
])

加

$client = new \GuzzleHttp\Client();
$request = $client->post('http://demo.website.com/api', [
    'body' => json_encode($dataArray)
]);
$response = $request->getBody();

在openssl.cafile文件中