表中的值采用以下格式
Returns Request for Order: 121212, RA Number:1654356, 4 Products:, 1 x "ABC" (11169595), Expected Action: Replace, 1 x "FGH" (11449119), Expected Action: Refund, 1 x "XCV" (11100873), Expected Action: Refund, 1 x "VVV" (11028561), Expected Action: Refund
-------------------------------------------------------------------------------------------------------------------------------
Returns Request for Order: 234354, RA Number:3465646, 3 Products:, 3 x "FGH" (11449119), Expected Action: Replace
-----------------------------------------------------------------------------------------------------
Returns Request for Order: 234355, RA Number:3465646, 3 Products:, 2 x "ABC" (11169595), Expected Action: Replace, 1 x "FGH" (11449119), Expected Action: Refund
以下是所需的o / p格式:
Order_Num REFUND_PRODUCTS REPLACE_PRODUCTS
121212 11449119,11100873,11028561 11169595
234354 11449119,11449119,11449119
234355 11449119 11169595,11169595
如果它的'2 x“ABC”(11169595)预期动作:REPLACE'然后在REPLACE_PRODUCT列下,则数字11169595'应该出现两次。
如果它'3 x ....'那么三次。类似于REFUND_PRODUCT
我怎么能这样做?
好的,只要您的格式保持一致,您就可以使用子字符串和找到的here函数的修改版本。我在这里创建了一个快速计数表,但是如果你已经有一个计数器或数字表,你可以将其交换掉。
正如肖恩在评论中提到的,如果这是一张大桌子,那么这需要一段时间才能运行。我认为没有任何方法可以解决这个问题,因为这是一个切断字符串的练习。
Declare @mytable as table (mydata varchar(4000))
Declare @myresults as table (order_num int, refund_products varchar(1000), replace_products varchar(1000))
declare @tally as table (t_idx int)
insert into @tally
select 1 UNION ALL
select 2 UNION ALL
select 3 UNION ALL
select 4 UNION ALL
select 5 UNION ALL
select 6 UNION ALL
select 7 UNION ALL
select 8 UNION ALL
select 9
INSERT INTO @mytable
Select 'Returns Request for Order: 121212 RA Number:1654356 4 Products: 1 x "ABC" (11169595) Expected Action: REPLACE 1 x "FGH" (11449119) Expected Action: REFUND 1 x "XCV" (11100873) Expected Action: REFUND 1 x "VVV" (11028561) Expected Action: REFUND' UNION ALL
Select 'Returns Request for Order: 234354 RA Number:3465646 3 Products: 3 x "FGH" (11449119) Expected Action: REPLACE' UNION ALL
Select 'Returns Request for Order: 234355 RA Number:3465646 3 Products: 2 x "ABC" (11169595) Expected Action: REPLACE 1 x "FGH" (11449119) Expected Action: REFUND'
insert into @myresults
Select
substring(mydata,charindex('Order:',mydata, 0)+7,6),
substring(
STUFF(
(Select ',' + pos_string from dbo.FindPatternLocation(mydata,'(') FOR XML PATH('')),1,1,'' ) ,10,500),
STUFF(
(Select ',' + substring(mydata ,charindex('(',mydata,0)+1,8) from @tally where t_idx<=substring(mydata,charindex('(',mydata,0)-10,1) FOR XML PATH('')),1,1,''
)
from @mytable
Select * from @myresults
功能:
CREATE FUNCTION dbo.FindPatternLocation
(
@string NVARCHAR(MAX),
@term NVARCHAR(255)
)
RETURNS TABLE
AS
RETURN
(
SELECT pos = Number - LEN(@term) ,
substring(@string, Number - LEN(@term)+1, 8) as pos_string
FROM (SELECT Number, Item = LTRIM(RTRIM(SUBSTRING(@string, Number,
CHARINDEX(@term, @string + @term, Number) - Number)))
FROM (SELECT ROW_NUMBER() OVER (ORDER BY [object_id])
FROM sys.all_objects) AS n(Number)
WHERE Number > 1 AND Number <= CONVERT(INT, LEN(@string)+1)
AND SUBSTRING(@term + @string, Number, LEN(@term)) = @term
) AS y);
作为该函数的替代方法,您可以将其用作第二列: -
substring(
STUFF(
(Select ',' + pos_string from
(SELECT pos = Number - LEN('(') ,
substring(mydata, Number - LEN('(')+1, 8) as pos_string
FROM (SELECT Number, Item = LTRIM(RTRIM(SUBSTRING(mydata, Number,
CHARINDEX('(', mydata + '(', Number) - Number)))
FROM (SELECT ROW_NUMBER() OVER (ORDER BY [object_id])
FROM sys.all_objects) AS n(Number)
WHERE Number > 1 AND Number <= CONVERT(INT, LEN(mydata)+1)
AND SUBSTRING('(' + mydata, Number, LEN('(')) = '('
) aa) bb FOR XML PATH('')),1,1,'' ) ,10,500)