具有一个字符串datetime,其中包含一个待处理的'AEST',需要将其删除,以便可以进行日期计算
要使用空白工作查找并替换'AEST'来手动完成此操作。但是要在不起作用的VBA中执行此操作。-例如,当有4个样本日期时,就会出现不一致,并且其中2个日期会转换为美国时间而不是AUS时间。-不知道这种不一致的根本原因
Sub KPIM_RptMth()
Range("H:H").Select
Selection.Replace What:="AEST", Replacement:="", LookAt:=xlPart, SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, ReplaceFormat:=False
End Sub
e.g. sample dates:
[REQ] WOC Date and Time
12-04-2019 01:03:32 PM AEST
22-06-2019 08:33:04 AM AEST
11-06-2019 03:30:00 PM AEST
17-06-2019 02:50:00 PM AEST
the correct output is:
[REQ] WOC Date and Time
12/04/2019 13:03
22/06/2019 8:33
11/06/2019 15:30
17/06/2019 14:50
the actual output after the VBA script above runs is:
[REQ] WOC Date and Time
4/12/2019 13:03
22-06-2019 08:33:04 AM
6/11/2019 15:30
17-06-2019 02:50:00 PM
问题是计算机无法知道此字符串日期具有哪种格式
12-04-2019 01:03:32 PM AEST
可能是以下两个
dd-mm-yyyy
mm-dd-yyyy
因此,您所做的就是让计算机进行猜测,然后它就会失败。即使是人类也无法说出两种格式中的哪一种是正确的。因此,作为字符串的日期和没有实际日期的日期几乎没有用(除非您具有有关格式的其他信息,而该信息不属于日期字符串本身)。
因此,[[唯一有效的解决方案将字符串转换为日期是如果您知道两种格式中的哪一种是正确的,请使用此信息将日期分割成几部分并使用DateSerial function用它创建一个真实的日期。
您将需要对每个单元格执行以下类似操作,作为字符串日期转换。示例
Public Sub ConvertTimeStampToRealDateTime()
Dim TimeStampString As String
TimeStampString = "12-04-2019 01:03:32 PM AEST"
'split by spaces
Dim SplitTimeStamp As Variant
SplitTimeStamp = Split(TimeStampString, " ")
'SplitTimeStamp(0) = "12-04-2019"
'SplitTimeStamp(1) = "01:03:32"
'SplitTimeStamp(2) = "PM"
'SplitTimeStamp(3) = "AEST"
'split date by dash
Dim SplitDate As Variant
SplitDate = Split(SplitTimeStamp(0), "-")
'SplitDate(0) = "12"
'SplitDate(1) = "04"
'SplitDate(2) = "2019"
'now we add the information which of the 3 split parts is day, month and year
'and put it together to a real date
Dim RealDate As Date
RealDate = DateSerial(SplitDate(2), SplitDate(1), SplitDate(0))
'cast time string into a date
Dim RealTime As Date
RealTime = SplitTimeStamp(1) & " " & SplitTimeStamp(2)
'casting from string to date works good for times but not for dates
'so we can do that with the time
'Add date and time to make it a datetime
Dim RealDateTime As Date
RealDateTime = RealDate + RealTime 'note that we need to ADD them mathematically (+) this is not a string concatenation (&)!!!
'AEST: This information about how many hours you need to add or subtract
' from this datetime to convert it into your desired time zone needs
' needs to be done manually
Dim RealDateTimeInMyZone As Date
RealDateTimeInMyZone = DateAdd("h", -3, RealDateTime) 'for example subtract 3 hours
End Sub
最后,您可以将实际的日期时间写入一个单元格,并用Range("A1").NumberFormat
将其格式化为所需的格式。图像1:字符串到日期的转换期间的变量值。
请注意,上面的代码仅是该概念的示例。如果需要使其牢固,则可能需要进行一些检查和错误处理,因为在意外的输入字符串上它将失败。此外,最好使用其中的一个函数来重新使用它,例如:
Public Function ConvertDDMMYYYYTimeStampToRealDateTime(ByVal TimeStampString As String) As Date End Function
Power Query
或Get & Transform
来完成此操作所有步骤都可以通过GUI完成
space
分隔符分隔列(仅最右边的实例)DateTime
作为格式,选择English(Australia)
作为语言环境现在,工作表将包含“真实的” Excel日期/时间,如果未按照您希望的格式设置,则只需更改单元格格式。
原始
结果
M代码
(您并不是真的需要它,但是如果将其粘贴到高级编辑器中,如果遇到问题,它将重新创建GUI步骤。如果使用此方法,则可能需要更改Table
名称。
let
Source = Excel.CurrentWorkbook(){[Name="Table1"]}[Content],
#"Split Column by Delimiter" = Table.SplitColumn(Source, "[REQ] WOC Date and Time", Splitter.SplitTextByEachDelimiter({" "}, QuoteStyle.Csv, true), {"[REQ] WOC Date and Time.1", "[REQ] WOC Date and Time.2"}),
#"Removed Columns" = Table.RemoveColumns(#"Split Column by Delimiter",{"[REQ] WOC Date and Time.2"}),
#"Changed Type with Locale" = Table.TransformColumnTypes(#"Removed Columns", {{"[REQ] WOC Date and Time.1", type datetime}}, "en-AU")
in
#"Changed Type with Locale"