POS：如何堆叠每件商品的价格以获取总价？

Question

（（尚未完成）我是编码新手，我有问题...我不知道如何获得总价。示例：我订购了5个Piato，然后键入end以显示结果或总计，但是它只说20，但是应该是100，因为20 + 20 + 20 + 20 + 20 = 100。显示正确的总价而不更改订购商品的方式？ （仅选择每个项目旁边提供的字母）

 import java.util.Scanner;
public class Point_Of_Sale_System_Real {

 static Scanner sc = new Scanner(System.in);
 public static void main(String[] args) {
 Intro();

 }
public static void Intro(){  

System.out.println("====================================");
System.out.println("Point of Sale System");    
System.out.println("WELCOME TO GRILLBY'S MINI MART!!!");  
System.out.println("Snowdin town, Underground city");   
System.out.println("====================================");
System.out.println("");
System.out.println("");



int Piatos = 20, Vcut = 20, Coke = 15, Pepsi = 15, Hiro = 8, Dewberry = 10, CheeseB = 25, GarlicB = 26, Small = 10, Medium = 18, CheeseF = 15, BBQF = 16;
System.out.println("                               MENU               ");
System.out.println("_____________________________________________________________________________");
System.out.println("        Chips                   Soda                 Biscuit");
System.out.println("");
System.out.println("[a]Piatos = Php 20.0     [c]Coke = Php 15.0   [e]Hiro = Php 8.0 ");
System.out.println("[b]V-cut = Php 20.0     [d]Pepsi = Php 15.0  [f]Dewberry = Php 10.0");
System.out.println("_____________________________________________________________________________");
System.out.println("        Burger                 Water                 Fries");
System.out.println("");
System.out.println("[g]Cheese = Php 25.0   [h]Small = Php 10.0    [i]Cheese = Php 15.0");
System.out.println("   Burger                                        fries");
System.out.println("");
System.out.println("[j]Garlic = Php 26.0   [k]Medium = Php 18.0     [l]BBQ = Php 16.0");
System.out.println("   Glazed                                         fries");
System.out.println("   Burger                          "); 

double itemtotal = 0, itemtotalvisible, itemlone = 0;

String Ia = "a";
String Ib = "b";
String Ic = "c";
String Ie = "e";
String If = "f";
String Ig = "g";
String Ih = "h";
String Ii = "i";
String Ij = "j";
String Ik = "k";
String Il = "l";


    System.out.println("====================================================================");
  System.out.println("*Choose from the menu*");
  System.out.println("Enter the letter that matches the item here: ");
      System.out.println("Type \"End\" to stop selecting from the menu." );

 //Pls work bro
  String itemselect = "";
  do {
      itemselect = sc.nextLine();   
      if (itemselect.equalsIgnoreCase(Ia)){
          itemlone = 0 + Piatos;
      }
      else if (itemselect.equalsIgnoreCase(Ib)){
          itemlone = 0 + Vcut;
      }
  }while (!itemselect.equalsIgnoreCase("end"));

 itemtotalvisible = itemlone + 0;
 System.out.println("Total" + itemtotalvisible);



}
}

Answer 1

每次在do-while循环中进行选择时，都需要更新itemtotalvisible。您仅将itemlone的最后一个值分配给itemtotalvisible。因此，因为您选择的最后一项是Piatos，所以itemtotalvisible等于一个Piatos项的值。

下面的代码不是完整的答案，但希望足以帮助您修复代码。

double itemtotalvisible = 0;
String itemselect = "";
do {
    itemselect = sc.nextLine();
    if (itemselect.equalsIgnoreCase(Ia)){
        itemlone = 0 + Piatos;
    }
    else if (itemselect.equalsIgnoreCase(Ib)){
        itemlone = 0 + Vcut;
    }
    itemtotalvisible += itemlone;
}while (!itemselect.equalsIgnoreCase("end"));

System.out.println("Total" + itemtotalvisible);