Python：在类继承中传递可选参数

Question

我不明白为什么我不能将可选参数设置为值。我总是收到一个空清单。我将参数设置为Nonetype以避免在那里存在可变类型。是由于我的父母班级的监督而不更新吗？还是其他吗？

class Human:
  def __init__(self,first,last,age,nicknames=None):
    self.first =first
    self.last = last
    self.age = age

    if nicknames is None:
      self.nicknames = []
    else:
      self.nicknames = nicknames


class NFL_QB:
  def __init__(self,td,comeback,lst=None):
    self.td = td
    self.comeback = comeback

    if lst is None:
      self.lst = []
    else:
      self.lst = lst


class College_QB:
  def __init__(self,c_td,c_comeback):
    self.c_td = c_td
    self.c_comeback = c_comeback


class Player(Human,NFL_QB,College_QB):
  def __init__(self,first,last,age,td,comebacks,c_td,c_comebacks,nicknames=None,lst=None):
    Human.__init__(self,first,last,age,nicknames=None)
    NFL_QB.__init__(self,td,comebacks,lst=None)
    College_QB.__init__(self,c_td,c_comebacks)




ply = Player('tom','brady',42,532,55,32,21,['toutchdown tom'],[2016])

Answer 1

将args传递给您的超类构造函数：

class Player(Human,NFL_QB,College_QB):
  def __init__(self,first,last,age,td,comebacks,c_td,c_comebacks,nicknames=None,lst=None):
    Human.__init__(self,first,last,age,nicknames=nicknames) # You were passing `None` here
    NFL_QB.__init__(self,td,comebacks,lst=lst)  # ...and here.
    College_QB.__init__(self,c_td,c_comebacks)




ply = Player('tom','brady',42,532,55,32,21,['toutchdown tom'],[2016])
print(ply.__dict__)