以 JSon 格式打印 Laravel 错误

Question

有谁知道如何使用 Json 格式的响应以及相应的 HTTP 错误和发生错误的描述性消息，使应用程序以一般方式返回任何异常，而不执行任何类型的重定向到 发生时间？

这是我想要的一个例子

{
"errors": [],
"exception":
"Illuminate\\Database\\Eloquent\\ModelNotFoundException",
"file":
"/var/www/project/vendor/laravel/framework/src/Illuminate/Database/Eloqu
ent/Builder.php",
"line": 598,
"message": "No query results for model
[App\\Models\\API\\ModelName].",
"statusCode": 404
}

我试图从 App/Exception/Handler.php 执行此操作

<?php

namespace App\Exceptions;

use Illuminate\Foundation\Exceptions\Handler as ExceptionHandler;
use Throwable;

class Handler extends ExceptionHandler
{
    /**
     * The list of the inputs that are never flashed to the session on validation exceptions.
     *
     * @var array<int, string>
     */
    protected $dontFlash = [
        'current_password',
        'password',
        'password_confirmation',
    ];

    /**
     * Register the exception handling callbacks for the application.
     */
    public function register(): void
    {
        $this->reportable(function (Throwable $e) {
            $Status = array('msg'=>$e);
            return response ($Status,$e);
        });
    }
}