有条件的地方？

Question

使用下表。我想获得Party_ID。我将只有NEW_ORG_ID和ORIGINAL_ID。

使用NEW_ORG_ID我希望使用MAX（USR_CRTE_TS）获取PARTY_ID，除非ORIGINAL_ID也匹配。然后我想要NEW_ORG_ID和ORIGINAL_ID匹配的PARTY_ID。

PARTY_ID          |DIRS_ID  |SUPPLIER_ID|ORIGINAL_ID|TRIANGLE_ID|NEW_ORG_ID|USR_CRTE_TS        |
------------------|---------|-----------|-----------|-----------|----------|-------------------|
5385606962        |476800490|5385606962 |NULL       |NULL       |69214683  |2018-09-27 04:56:13|
69214683          |476800490|NULL       |2740793553 |NULL       |69214683  |2018-09-27 04:54:15|

我尝试了以下内容。请记住，我仅为此示例硬编码NEW_ORG_ID和ORIGINAL_ID。在现实世界中，示例NEW_ORG_ID和ORIGINAL_ID由查询的另一部分提供。

    SELECT DISTINCT PARTY_ID 
FROM UNIQUE_IDS UNQ 
WHERE   
( 
        CASE
            WHEN ( 
                    SELECT ts.PARTY_ID
                    FROM UNIQUE_IDS ts 
                    WHERE (ts.NEW_ORG_ID = '69214683' AND ts.ORIGINAL_ID = '2740793553') 
                 ) IS NOT NULL
            THEN 
                (
                    SELECT ts.PARTY_ID 
                    FROM UNIQUE_IDS ts 
                    WHERE (ts.NEW_ORG_ID = '69214683' AND ts.ORIGINAL_ID = '2740793553') 
                )
            ELSE 
                (
                    SELECT ts.PARTY_ID
                    FROM UNIQUE_IDS ts 
                    WHERE ts.NEW_ORG_ID = '69214683'
                    AND ts.USR_CRTE_TS = (  
                                            SELECT MAX(ts.USR_CRTE_TS) 
                                            FROM UNIQUE_IDS ts 
                                            WHERE ts.NEW_ORG_ID = '69214683'
                                        )--xref.SBL_GLOB_CSTMR_ID)
                )
        END
) = UNQ.NEW_ORG_ID 

;

Answer 1

您可以使用ROW_NUMBER()解析函数来获得标记为数字1的“最佳”匹配（首先是ORIGINAL_ID，然后是USR_CRTE_TS），并对其进行过滤：

SELECT PARTY_ID
FROM   (
            SELECT  PARTY_ID,
                    USR_CRTE_TS,  
                    ROW_NUMBER() OVER (
                        PARTITION BY PARTY_ID 
                        ORDER BY     CASE ORIGINAL_ID 
                                         WHEN '2740793553' THEN 0 
                                         ELSE 1 
                                     END,
                                     USR_CRTE_TS DESC
                    ) RN
            FROM    UNIQUE_IDS
            WHERE   NEW_ORG_ID = '69214683'
        )
WHERE   RN = 1

如果USR_CRTE_TS可以是NULL，那么在最后添加另一个条件以符合你的要求：

AND     (ORIGINAL_ID = '2740793553' OR USR_CRTE_TS IS NOT NULL)

When the criteria are selected elsewhere

您可以使用WITH子句逐层构建查询。因此，假设您已经有工作逻辑来选择两个“参数”，然后将其放在with子句中，如下所示：

WITH CRIT(SEL_ORG_ID, SEL_ORIGINAL_ID) AS (
    SELECT '69214683', '2740793553' FROM DUAL -- this is just an example
)

...然后像这样继续查询：

), BASE AS (
    SELECT  UI.PARTY_ID,
            UI.USR_CRTE_TS,
            UI.ORIGINAL_ID,
            CRIT.SEL_ORIGINAL_ID,
            ROW_NUMBER() OVER (
                PARTITION BY UI.PARTY_ID 
                ORDER BY     CASE UI.ORIGINAL_ID 
                                 WHEN CRIT.SEL_ORIGINAL_ID THEN 0 
                                 ELSE 1 
                             END,
                             UI.USR_CRTE_TS DESC
            ) RN
    FROM    UNIQUE_IDS UI,
            CRIT
    WHERE   UI.NEW_ORG_ID = CRIT.SEL_NEW_ORG_ID
)
SELECT PARTY_ID
FROM   BASE
WHERE  RN = 1
AND    (ORIGINAL_ID = SEL_ORIGINAL_ID OR USR_CRTE_TS IS NOT NULL)

Answer 2

我会使用row_number()条件排序：

select party_id 
  from (
    select party_id, 
           row_number() over (order by case when original_id = '2740793553' then 1 end, 
                                       usr_crte_ts desc) rn
      from unique_ids unq
      where new_org_id = '69214683')
  where rn = 1

dbfiddle demo

如果original_id匹配，那么row具有更高的优先级。第二优先是最高的usr_crte_ts。最后我们采取第一个最好的行。