如果主教/女王（Java）块被阻止，则象棋游戏删除对角线运动

Question

我正在用Java制作国际象棋游戏。

[我做了一个JFrame，让我可以创建棋子，这就是为什么我可以对任何棋子进行所有可能动作的原因（并且我将制作出比普通棋更多的棋子）。

但是我有一个小问题，我试图删除主教的动向已经过了两天，而且看起来并不那么容易。

我有一个包含正子的数组，看起来像这样：

_______ PIECES[x][y] //1 is black 0 is no piece 2 is white
1 1 1 1 1 1 1 1 
1 1 1 1 1 1 1 1 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
2 2 2 2 2 2 2 2 
2 2 2 2 2 2 2 2 
_______ legalmoves[y][x] //Containing legal moves 1 is move/attack 0 cannot move there
// ( (x,y) (its y x in this tab)
// is reverse because it needs to be somewhere else in the code this is not a big deal)
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
1 0 0 0 0 0 0 0 
0 1 0 0 0 0 0 0 
0 0 1 0 0 0 0 0 
0 0 0 1 0 0 0 1 
0 0 0 0 1 0 1 0 
0 0 0 0 0 0 0 0 
My piece X,Y : 5 7

[当需要知道一件作品的合法移动并且检测到一件作品有对角线移动时调用该函数为此，这里的法律行动应该看起来像这样

0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0

因为还有其他块（白色）阻碍了移动

[在此先感谢您，如果您愿意（如果它可以帮助您帮助我），我可以为您提供菜鸟运动的功能（当检测到后腿倾斜运动时，它也可以为女王/王后使用，无论我创造了什么，这种动作）。车的代码：

boolean t = false;
   if (hasRectMoves) {
    System.out.println(x + " XY " + y);
    System.out.println("HAS RECT MOVES !");
    System.out.println("_______ PIECES");
    for (int i = 0; i < 8; i++) {
     for (int j = 0; j < 8; j++) {
      System.out.print(pieces[i][j] + " ");
     }
     System.out.println("");
    }
    System.out.println("_______ RES");
    for (int i = 0; i < 8; i++) {
     //System.out.println("i = "+ i);
     for (int j = 0; j < 8; j++) {
      System.out.print(res[j][i] + " ");
     }
     System.out.println("");
    }
    System.out.println("My piece : " + (x + 1) + " " + (y + 1));
    boolean test = true;

    for (int i = y; i >= 0; i--) {
     //res[x+1][i]=0;
     if (test) {
      if (pieces[i][x + 1] != 0) {
       if (this.isBlack) {
        if (pieces[i][x + 1] == 1)
         res[x + 1][i] = 4;//4 to seen in the array where it makes move illegal
       }
       if (!this.isBlack) {
        if (pieces[i][x + 1] == 2)
         res[x + 1][i] = 4;
       }
       // System.out.println(i + " "+ pieces[i][y+1] + " "  + (x+1) + "=x y="+ (y+1)); 
       test = false;
      }
     } else {
      res[x + 1][i] = 4;
     }

    }
    test = true;
    for (int i = x; i >= 0; i--) {
     //res[x+1][i]=0;
     if (test) {
      if (pieces[y + 1][i] != 0) {
       if (this.isBlack) {
        if (pieces[y + 1][i] == 1)
         res[i][y + 1] = 4;
       }
       if (!this.isBlack) {
        if (pieces[y + 1][i] == 2)
         res[i][y + 1] = 4;
       }
       // System.out.println(i + " "+ pieces[i][y+1] + " "  + (x+1) + "=x y="+ (y+1)); 
       test = false;
      }
     } else {
      res[i][y + 1] = 4;
     }

    }
    test = true;
    for (int i = x + 2; i < 8; i++) {
     //res[x+1][i]=0;
     if (test) {
      if (pieces[y + 1][i] != 0) {
       if (this.isBlack) {
        if (pieces[y + 1][i] == 1)
         res[i][y + 1] = 4;
       }
       if (!this.isBlack) {
        if (pieces[y + 1][i] == 2)
         res[i][y + 1] = 4;
       }
       // System.out.println(i + " "+ pieces[i][y+1] + " "  + (x+1) + "=x y="+ (y+1)); 
       test = false;
      }
     } else {
      res[i][y + 1] = 4;
     }

    }
    test = true;
    for (int i = y + 2; i < 8; i++) {
     //res[x+1][i]=0;
     if (test) {
      if (pieces[i][x + 1] != 0) {
       if (this.isBlack) {
        if (pieces[i][x + 1] == 1)
         res[x + 1][i] = 4;
       }
       if (!this.isBlack) {
        if (pieces[i][x + 1] == 2)
         res[x + 1][i] = 4;
       }
       // System.out.println(i + " "+ pieces[i][y+1] + " "  + (x+1) + "=x y="+ (y+1)); 
       test = false;
      }
     } else {
      res[x + 1][i] = 4;
     }
    }

Answer 1

不错的项目。

我在主体中写了一个小例子，所以您可以尝试一下。当然还有改进的空间。

我的输出：

3 XY 4
HAS RECT MOVES !
_______ PIECES
1 1 1 1 1 1 1 1 
1 1 1 1 1 1 1 1 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
2 2 2 2 2 2 2 2 
2 2 2 2 2 2 2 2 
_______ RES
0 0 0 0 0 0 0 5 
6 0 0 0 0 0 6 0 
0 7 0 0 0 7 0 0 
0 0 8 0 8 0 0 0 
0 0 0 9 0 0 0 0 
0 0 8 0 8 0 0 0 
0 7 0 0 0 7 0 0 
6 0 0 0 0 0 6 0 
My piece : 3 4
_______ legalmoves
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 7 0 0 0 7 0 0 
0 0 8 0 8 0 0 0 
0 0 0 9 0 0 0 0 
0 0 8 0 8 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 

主教的位置标有9。我给每个字段加一个从8倒数开始的等级，该值规定了该字段距主教的距离。 （我希望这是英文吗？）

然后您必须将矩形分成4个子。对于每个子项，您必须分别计算合法移动。

请尝试一下。如果您有任何疑问，请告诉我。

public static void main(String[] args) throws Exception{

        int pieces[][] = new int[8][8];
        int res[][] = new int[8][8];

        int x = 3;
        int y = 4;

        System.out.println(x + " XY " + y);
        System.out.println("HAS RECT MOVES !");
        System.out.println("_______ PIECES");
        for (int i = 0; i < 8; i++) {
            for (int j = 0; j < 8; j++) {
                if(i<2){ pieces[i][j] = 1; }
                if(i>5){ pieces[i][j] = 2; }

                System.out.print(pieces[i][j] + " ");
            }
            System.out.println("");
        }
        System.out.println("_______ RES");
        for (int i = 0; i < 8; i++) {
            for (int j = 0; j < 8; j++) {
                res[i][j] = checkField(i, j, x, y);
                System.out.print(res[i][j] + " ");
            }
            System.out.println("");
        }
        System.out.println("My piece : " + (x) + " " + (y));
        System.out.println("_______ legalmoves");
        // 1. section:
        System.out.println("1. section:");
        calcSection(pieces, res, 0, 0, x, y);
        // 2. section:
        System.out.println("2. section:");
        calcSection(pieces, res, 0, y, x, 7);
        // 3. section:
        System.out.println("3. section:");
        calcSection(pieces, res, x, 0, 7, y);
        // 4. section:
        System.out.println("4. section:");
        calcSection(pieces, res, x, y, 7, 7);

        for (int i = 0; i < 8; i++) {
            for (int j = 0; j < 8; j++) {
                System.out.print(res[i][j] + " ");
            }
            System.out.println("");
        }

    }
    public static int[][] calcSection(int[][] pieces, int[][] res, int recStartX, int recStartY, int recEndX, int recEndY){
        System.out.println(recStartX+ ":"+ recStartY + ":"+ recEndX +":" +recEndY);
        System.out.println("res[i][j] = " + res[5][7]);
        for (int k = 8; k > 0; k--) {
            for (int i = recStartX; i <= recEndX; i++) {
                for (int j = recStartY; j <= recEndY; j++) {
                    if(res[j][i] == k){
                        if(pieces[j][i] > 0){
                            for (int l = recStartX; l <= recEndX; l++) {
                                for (int m = recStartY; m <= recEndY; m++) {
                                    if(res[m][l] <= k){
                                        res[m][l] = 0;
                                    }
                                }
                            }       
                            return res;
                        }
                    }
                }
            }
        }
        return res;        
    }

    public static int checkField(int fieldX, int fieldY, int x, int y){
        //x = 3;
        //y = 2;
        if((fieldY == x )&(fieldX == y )){
            return 9;
        }
        else{
            for (int i = 0; i < 8; i++) {
                if((fieldY == x+i )&(fieldX == y+i )){
                    return 9-i;
                } 
                else if((fieldY == x+i )&(fieldX == y-i )){
                    return 9-i;
                } 
                else if((fieldY == x-i )&(fieldX == y+i )){
                    return 9-i;
                }
                else if((fieldY == x-i )&(fieldX == y-i )){
                    return 9-i;
                }
            }
        }
        return 0;
    }
}