第二交易仍然是首先完成之后等待

问题描述 投票:0回答:1

接连运行在SSMS一个2个窗口在同一个脚本用几秒钟的延迟。 我开始后的第二个实例完成,但第一个将保持锁定状态,直到我关闭第二窗口。这是怎么回事吗?为什么不释放后COMMIT锁?

SET TRAN ISOLATION LEVEL SERIALIZABLE
BEGIN TRAN

SELECT * FROM dbo.t1
WHERE id IN (1,3)

WAITFOR DELAY '00:00:20'

UPDATE t1 SET InUse=0
WHERE id IN (1,3)

COMMIT

编辑:

表结构如下:

CREATE TABLE [dbo].[t1](
    [id] [INT] NOT NULL,
    [InUse] [BIT] NOT NULL DEFAULT ((0)),
PRIMARY KEY CLUSTERED 
(
    [id] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
sql-server tsql transactions locks
1个回答
1
投票

您应该更新与表结构你的问题。

当你没有指定表中是否有任何索引我想没有发生,即dbo.t1heap

在这种情况下,你会得到经典deadlock

session1想从表中select,需要S它读取任何行,因为对index整个表被读出并在桌子上dbo.t1持有该项交易的整个过程中没有S-lock

在同时session2做同样的,它也获取表S-lock并保持。

Session1现在需要将其S-lock为了做IXupdate转换,它是由session2持有Sdbo.t1阻止。

session2试图做同样的它会导致死锁,因为两个会话需要IX无一不是由其他会话锁定。

以下是相应的僵局图:

deadlock-list
 deadlock victim=process155d1d498
  process-list
   process id=process155d1d498 taskpriority=0 logused=0 waitresource=OBJECT: 26:1765581328:0  waittime=16222 ownerId=5528849 transactionname=user_transaction lasttranstarted=2019-02-07T13:39:38.837 XDES=0x15ec1c3a8 lockMode=IX schedulerid=4 kpid=8140 status=suspended spid=54 sbid=0 ecid=0 priority=0 trancount=2 lastbatchstarted=2019-02-07T13:39:38.833 lastbatchcompleted=2019-02-07T13:39:38.833 lastattention=2019-02-07T13:38:49.187 clientapp=Microsoft SQL Server Management Studio - Query hostname=pppp hostpid=12276 loginname=FINCONSGROUP\anna.savchenko isolationlevel=serializable (4) xactid=5528849 currentdb=26 lockTimeout=4294967295 clientoption1=671098976 clientoption2=390200
    executionStack
     frame procname=adhoc line=9 stmtstart=248 stmtend=334 sqlhandle=0x02000000f445021276fec0f5ec119082f65611ce316a4d280000000000000000000000000000000000000000
UPDATE t1 SET InUse=0
WHERE id IN (1,3)     
    inputbuf
SET TRAN ISOLATION LEVEL SERIALIZABLE
BEGIN TRAN
SELECT * FROM dbo.t1
WHERE id IN (1,3)
WAITFOR DELAY '00:00:20'
UPDATE t1 SET InUse=0
WHERE id IN (1,3)
COMMIT
   process id=process15649f868 taskpriority=0 logused=0 waitresource=OBJECT: 26:1765581328:0  waittime=1212 ownerId=5529084 transactionname=user_transaction lasttranstarted=2019-02-07T13:39:53.847 XDES=0x15ec1d048 lockMode=IX schedulerid=3 kpid=15516 status=suspended spid=57 sbid=0 ecid=0 priority=0 trancount=2 lastbatchstarted=2019-02-07T13:39:53.847 lastbatchcompleted=2019-02-07T13:39:53.847 lastattention=1900-01-01T00:00:00.847 clientapp=Microsoft SQL Server Management Studio - Query hostname=pppp hostpid=12276 loginname=FINCONSGROUP\anna.savchenko isolationlevel=serializable (4) xactid=5529084 currentdb=26 lockTimeout=4294967295 clientoption1=671098976 clientoption2=390200
    executionStack
     frame procname=adhoc line=9 stmtstart=248 stmtend=334 sqlhandle=0x0200000093b3ba1c08d586d1f142f473a7c8996074a369fc0000000000000000000000000000000000000000
UPDATE t1 SET InUse=0
WHERE id IN (1,3)     
    inputbuf
SET TRAN ISOLATION LEVEL SERIALIZABLE
BEGIN TRAN
SELECT * FROM dbo.t1
WHERE id IN (1,3)
WAITFOR DELAY '00:00:20'
UPDATE t1 SET InUse=0
WHERE id IN (1,3)
COMMIT    
  resource-list
   objectlock lockPartition=0 objid=1765581328 subresource=FULL dbid=26 objectname=parts.dbo.t1 id=lock152c2d300 mode=S associatedObjectId=1765581328
    owner-list
     owner id=process15649f868 mode=S
     owner id=process15649f868 mode=IX requestType=convert
    waiter-list
     waiter id=process155d1d498 mode=IX requestType=convert
   objectlock lockPartition=0 objid=1765581328 subresource=FULL dbid=26 objectname=parts.dbo.t1 id=lock152c2d300 mode=S associatedObjectId=1765581328
    owner-list
     owner id=process155d1d498 mode=S
     owner id=process155d1d498 mode=IX requestType=convert
    waiter-list
     waiter id=process15649f868 mode=IX requestType=convert
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