超载赋值运算符失效

Question

我有一个班 雇员. (我的一些评论在我添加成员任务和taskList时没有更新，我对此表示歉意。)

Employee.h

#include <string>
#include <iostream>
using namespace std;
class Employee {
private:
    string employee_name;
    string employee_ssn;
    string * taskList;  //stores an array of tasks for the employee to do
    int tasks;  //stores the number of tasks an employee needs to do
public:
    //constructors  
    Employee(); //default - nothing
    Employee(string, string, string a[], int numOfTasks);   //sets both ssn and name
    ~Employee(); //destructor
    //copy constructor:
    Employee(const Employee &emp);
    Employee & operator =(const Employee& source);
    void set_name(string);      //sets name in program
    void set_ssn(string);       //sets ssn in program
    string get_ssn();           //returns ssn as string
    string get_name();          //returns emp name as string
    void display();             //displays both on two separate lines
};

Employee.cpp

#include "Employee.h"
//constructors  
//default constructor makes the object empty
Employee::Employee() {
    taskList = nullptr;
    return;
}
//constructor sets both name and ssn
Employee::Employee(string x, string y, string a[], int numOfTasks) {
    employee_name = x;
    employee_ssn = y;
    tasks = numOfTasks;
    taskList = a;
    return;
}
//destructor
Employee::~Employee() {
    delete [] taskList;
}
//copy constructor
Employee::Employee(const Employee & source) {
    //copy simple member variables
    employee_name = source.employee_name;
    employee_ssn = source.employee_ssn;
    tasks = source.tasks;
    //allocate new dynamic array for taskList
    taskList = new string[source.tasks];
    //copy values from one taskList to another
    for (int i = 0; i < tasks; i++)
        taskList[i] = source.taskList[i];
    return;
}
//assignment operator overloading
Employee & Employee::operator =(const Employee& source) {
    cout << "Calling the assignment operator overloader.\n";
    //check for self assignment
    if (this == &source)
        return *this;   //avoid doing extra work

    employee_name = source.employee_name;
    employee_ssn = source.employee_ssn;
    tasks = source.tasks;

    cout << "Substituting 'task list'\n";
    //delete former taskList
    //if (taskList != nullptr)
        delete[] taskList;
    cout << "TaskList deleted.\n";
    //allocate new one with same capacity
    taskList = new string[source.tasks];
    //copy values from one to the oher
    for (int i = 0; i < tasks; i++)
        taskList[i] = source.taskList[i];
    cout << "Function complete.\n";
    return *this;
}

//postcon: name is set to inputted string
void Employee::set_name(string s) {
    employee_name = s;
    return;
}
//postcon: ssn is set to inputted string
void Employee::set_ssn(string s) {
    employee_ssn = s;
    return;
}
//returns ssn as string
string Employee::get_ssn() {
    return employee_ssn;
}
//returns employee name as string
string Employee::get_name() {
    return employee_name;
}
//precon: name and ssn are both assigned
//postcon: name and ssn printed to the screen w/ labels on two lines
void Employee::display() {
    cout << "Name: " << employee_name << endl;
    cout << "SSN: " << employee_ssn << endl;
    cout << "Tasks:\n";
    for (int i = 0; i < tasks; i++)
        cout << i + 1 << ". " << taskList[i] << endl;
    return;
}

指导我们实现了复制构造函数和赋值重载，还特别指导我们在主程序中让各个Employee对象动态分配。

我似乎遇到的问题是使用赋值重载进行交换。

employee_driver.cpp

#include "Employee.h"
#include <iostream>

int main() {
    //tasks for each employee to do:
    //Tasks to be assigned to Marcy:
    string tasks[2] = {"Send emails", "Prepare meeting brief"};
    //Taks to be assigned to Michael:
    string tasks2[3] = {"Stock up on pens", "Send emails", "Organize union"};

    Employee *emp1 = new Employee("Marcy", "678091234", tasks, 2);
    Employee *emp2 = new Employee("Michael", "123994567", tasks2, 3);

    //display data before swap
    emp1->display();
    cout << endl;
    emp2->display();
    cout << endl;

    //swap employees
    Employee temp(*emp1);   //using copy constructor to copy first employee into temporary
    *emp1 = *emp2;
    *emp2 = temp;   //uses overloaded assignment operator to copy values of temp into emp2; Marcy's data is now in Michael's pointer

    //display after swap
    cout << "\n\nAfter swap:\n\n";
    emp1->display();
    cout << endl;
    emp2->display();



    //free heap
    delete emp1;
    delete emp2;
    //delete emp3;

    return 0;
}

这个问题似乎发生在这里。*emp1 = *emp2; (在主程序的底部)，但我不明白为什么；希望得到任何帮助。我可以绕过它，但我认为这不是练习的目的，我想知道为什么这个语句不能正常工作。

谢谢。

Answer 1

在构造函数中

Employee::Employee(string x, string y, string a[], int numOfTasks) {
    employee_name = x;
    employee_ssn = y;
    tasks = numOfTasks;
    taskList = a;
    return;
}

你只需将传递的指针 a 在数据成员中 taskList,

在主要的数组中

string tasks[2] = {"Send emails", "Prepare meeting brief"};
//Taks to be assigned to Michael:
string tasks2[3] = {"Stock up on pens", "Send emails", "Organize union"};

不是动态分配的。所以你不能在复制赋值操作符中调用删除[]操作符来删除这样的数组。

delete[] taskList;

你需要在构造函数中动态地分配数组，这个数组的指针作为参数传递给构造函数。

还要注意的是，在默认的构造函数中，你需要在数据成员中设置 tasks 到0。