如何注入随机数。加特林的用户?

问题描述 投票:0回答:1

我想随机注入没有。加特林的用户例如,

前10秒,100个用户

接下来的15秒,25位用户,

接下来的2秒,1000个用户等等..

具有随机用户数的随机时间

我发现的一个复杂的解决方法如下:

val r=new scala.util.Random
  setUp(
    scn.inject(

         constantUsersPerSec(10) during(10 seconds) randomized,
             constantUsersPerSec(10+r.nextInt(500)) during(15 seconds) randomized,
             constantUsersPerSec(210+r.nextInt(500)) during(25 seconds) randomized,
             constantUsersPerSec(510+r.nextInt(520)) during(55 seconds) randomized,
             constantUsersPerSec(170+r.nextInt(100)) during(5 seconds) randomized,
             constantUsersPerSec(270+r.nextInt(1010)) during(5 seconds) randomized,
             constantUsersPerSec(710+r.nextInt(5100)) during(1 minute) randomized,
             constantUsersPerSec(5+r.nextInt(40)) during(100 seconds) randomized,
             constantUsersPerSec(710+r.nextInt(5200)) during(15 seconds) randomized,
             constantUsersPerSec(0+r.nextInt(20)) during(10 seconds) randomized,


         constantUsersPerSec(10) during(10 seconds) randomized,
             constantUsersPerSec(10+r.nextInt(500)) during(15 seconds) randomized,
             constantUsersPerSec(210+r.nextInt(500)) during(25 seconds) randomized,
             constantUsersPerSec(510+r.nextInt(520)) during(55 seconds) randomized,
             constantUsersPerSec(170+r.nextInt(100)) during(5 seconds) randomized,
             constantUsersPerSec(270+r.nextInt(1010)) during(5 seconds) randomized,
             constantUsersPerSec(710+r.nextInt(5100)) during(1 minute) randomized,
             constantUsersPerSec(5+r.nextInt(40)) during(100 seconds) randomized,
             constantUsersPerSec(710+r.nextInt(5200)) during(15 seconds) randomized,

             constantUsersPerSec(1) during(10 seconds),

           ).protocols(kafkaConf))

有没有简单的方法来做到这一点?

换句话说,有没有办法注入循环?

P.S:我尝试了repeat()的场景,但这完全是另一回事。它不是调用一次,而是调用n次,即它为每个用户执行动作n次。

scala gatling
1个回答
1
投票

.inject方法可以采用一系列注入步骤,因此您只需使用一个函数来生成该数组

val r=new scala.util.Random

setUp(
    scn.inject(
        (1 to 10).map(i => constantUsersPerSec(r.nextInt(500)) during (r.nextInt(30) seconds) randomized)
    )
).protocols
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