嵌套的NSArray / NSDictionary问题

问题描述 投票:1回答:2

我有一个包含几个NSArrayNSDictionaries

我有一个包含ID字符串的NSString

我想要做的是迭代NSDictionaries,直到找到与NSString相匹配的对象。然后我想要返回整个NSDictionary

我对iPhone开发还不熟悉,所以我可能错过了一些明显的东西...提前谢谢。 :)

编辑,这是保存的.plist文件:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<array>
    <dict>
        <key>date</key>
        <string>2011/05/20</string>
        <key>id</key>
        <string>1282007740</string>
        <key>name</key>
        <string>Test item name</string>
        <key>niceDate</key>
        <string>May 20, 2011</string>
    </dict>
    <dict>
        <key>date</key>
        <string>2010/08/15</string>
        <key>id</key>
        <string>1282075925</string>
        <key>name</key>
        <string>Test. Nothing to see here.</string>
        <key>niceDate</key>
        <string>Aug 15, 2010</string>
    </dict>
</array>
</plist>

假设我的NSString是“1282075925”。我想获得匹配的id键的字典。

iphone objective-c nsarray nsdictionary
2个回答
3
投票

这段代码应该做你想要的 - 最后,dict将指向你正在搜索的NSDictionary,如果没有匹配的字典,它将是nil

// (These are assumed to exist)
NSArray *dictionaries;
NSString *idToFind; 



NSDictionary *dict = nil;
for (NSDictionary *aDict in dictionaries) {
    if ([[aDict objectForKey:@"id"] isEqualToString:idToFind]) {
        dict = aDict;
        break;
    }
}

2
投票

如果您正在搜索@“12345”,并使用@“id”键

for (NSDictionary* dictionary in array1) {
   id value = [dictionary valueForKey:@"id"];
   if ([value isKindOfClass:[NSString class]]) {
      NSString* string = (NSString*) value;
      if ([string isEqualToString:@"12345"]) {
          return dictionary;
      }
   }
}
return nil;
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