我正在为我的应用程序编写UI测试，该应用程序使用UIWebView作为其内容。当按下webview中的按钮时，它会将测试用例写入如下：
func testExample() {
let app = XCUIApplication()
app.staticTexts["Log In"].tap()
}
这里的问题是，如果应用程序处于不同的本地化（例如“de-DE”），则不存在具有文本“登录”的按钮。取而代之的是“Anmelden”。我尝试了以下内容，但它们都不起作用：
Localizable.strings版本：
func testExample() {
let name = NSLocalizedString("Log In", comment: "")
let app = XCUIApplication()
app.staticTexts[name].tap()
}
和
public class Titles {
var homeScreenLogIn = "Log In"
}
public class TitlesDE: Titles {
override init() {
super.init()
homeScreenLogIn = "Anmelden"
}
}
...
func testExample() {
titles = TitlesDE()
let name = titles.homeScreenLogIn
let app = XCUIApplication()
app.staticTexts[name].tap()
}
UI测试失败 - 找到多个匹配项：
问题是我似乎无法弄清楚如何将数据转储到调试/测试输出，因为print()似乎不起作用。
您应该使用所有accessibilityIdentifier对象都具有的UIKit属性，因为此字符串未本地化，它仅用于UI自动化。
也就是说，当你使用UIWebView的内容时，似乎没有一个简单的解决方案。
这是我的解决方案，我将字符串对象扩展为包含.localized（）...您可以忽略（或更改）所有bundleName逻辑，因为它特定于我的项目，其中shell脚本移动/重命名本地化包非常具体的方式，但基本上，您需要从设备的当前设置语言中获取软件包的目录名称。还要注意，要使这项工作，我必须添加到我的UI测试目标“复制捆绑资源”应用程序的Localizable.strings和Localizable.stringsdict
使用案例：app.buttons [“Tap Me！”。localized（）]。tap（）app.staticTexts [“在App中显示的本地化字符串值”] .tw（）
请记住，您调用.localized（）的字符串必须在应用程序的Localizable包中定义，如果不是，那么它不是一个在设备语言更改时将转换的字符串。
extension String {
func localized() -> String {
// all this shit with bundleName is here only because we have a shell script that
// renames/moves all of our localization folders
var bundleName:String = deviceLanguage.stringByReplacingOccurrencesOfString("_", withString: "-")
let secondaryBundleNameParts = deviceLanguage.componentsSeparatedByString("-")
let secondaryBundleNamePartOne = secondaryBundleNameParts[0]
let secondaryBundleNamePartTwo = secondaryBundleNameParts.count > 1 ? secondaryBundleNameParts[1] : ""
let thirdBundleName = "\(secondaryBundleNamePartOne)-\(secondaryBundleNamePartTwo.uppercaseString)"
if secondaryBundleNamePartOne == "es" {
bundleName = secondaryBundleNamePartTwo == "ES" ? "es" : thirdBundleName
}
else if secondaryBundleNamePartOne == "pt" {
bundleName = secondaryBundleNamePartTwo == "BR" ? "pt" : thirdBundleName
}
else if secondaryBundleNamePartOne == "zh" {
bundleName = secondaryBundleNamePartTwo == "CN" ? "zh-Hans" : "zh-Hant"
}
else {
bundleName = secondaryBundleNamePartOne
}
var bundlePath:String? = NSBundle(forClass: FGUITestCase.self).pathForResource(bundleName, ofType: "lproj")
if bundlePath == nil {
bundlePath = NSBundle(forClass: FGUITestCase.self).pathForResource(deviceLanguage, ofType: "lproj")
if bundlePath == nil {
bundlePath = NSBundle(forClass: FGUITestCase.self).pathForResource(bundleName, ofType:nil)
if bundlePath == nil {
bundlePath = NSBundle(forClass: FGUITestCase.self).pathForResource(deviceLanguage, ofType:nil)
if bundlePath == nil {
for var i=0; i<100; i++ {
NSLog("OMG, WTF, Localization Bundle Not Found!: \(bundleName) || \(deviceLanguage)")
print("OMG, WTF, Localization Bundle Not Found!: \(bundleName) || \(deviceLanguage)")
}
}
}
}
}
let bundle = NSBundle(path:bundlePath!)
return NSLocalizedString(self, bundle:bundle!, comment: "")
}
subscript (i: Int) -> Character {
return self[self.startIndex.advancedBy(i)]
}
subscript (i: Int) -> String {
return String(self[i] as Character)
}
subscript (r: Range<Int>) -> String {
let start = startIndex.advancedBy(r.startIndex)
let end = start.advancedBy(r.endIndex - r.startIndex)
return self[Range(start: start, end: end)]
}
}
我能够处理这个问题的方法是创建一个Localization类，它包含不同UI元素的翻译字典，可以使用String键提取，该键对应用程序中的Web视图元素是唯一的。
要使用的定位使用全局变量localization来设置，该变量可以在测试期间的任何点设置，例如，在setUp()期间。
使用枚举表示本地化。
注意：这是一个非常粗略的实现，因为在字典上验证的方式并不多 - 创建一个本地化集类并使用[String: LocalizedIdentifierSet]字典将是一个更可靠的解决方案。
var localization = .Germany
class Localization {
/// Dictionary containing localizations for each available localisation
private static var localizations: [String: [Localization: String]] = [
"signOutLink": [
.UnitedKingdom: "SIGN OUT",
.UnitedStates: "SIGN OUT",
.France: "DÉCONNEXION",
.Germany: "ABMELDEN",
.Italy: "ESCI",
.Spain: "SALIR",
.Australia: "SIGN OUT",
.Russia: "ВЫЙТИ"
],
"appSettingsLink": [
.UnitedKingdom: "App Settings",
.UnitedStates: "App Settings",
.France: "Réglages",
.Germany: "App-Einstellungen",
.Italy: "Impostazioni dell'App",
.Spain: "Ajustes de la App",
.Australia: "App Settings",
.Russia: "Ajustes de la App"
]
]
/**
Returns a String containing the localized identifier for the element with the given `identifier`, for the currently-selected `localization`.
- Parameter identifier: String identifier for the element you want to retrieve the localized query string for.
- Returns: String to be used for querying the view hierarchy to find the element with `identifier`.
*/
class func getLocalizedQueryStringForElementWithIdentifier(identifier: String) -> String? {
let localizationsForElement = localizations[identifier]
let queryString = localizationsForElement?[localization]
return queryString
}
}
然后，您可以使用此类检索您在查询中使用的标识符：
let textIdentifier = Localization.getLocalizedQueryStringForElementWithIdentifier("signOutLink")
let textElement = app.staticTexts[textIdentifier!]
textElement.tap()
我终于用测试函数中的代码实现了它：
let locale = Locale.current.identifier
print(locale)
var tap1 = "STRING OF UI TEST 1 in ENGLISH"
var tap2 = "STRING OF UI TEST 2 in ENGLISH"
if (locale == "fr_US" || locale == "fr" || locale == "fr_FR" || locale == "fr_CA") {
tap1 = "STRING OF UI TEST 1 in FRENCH"
tap2 = "STRING OF UI TEST 2 in FRENCH"
}
else if (locale == "es_US" || locale == "es_ES" || locale == "es") {
tap1 = "STRING OF UI TEST 1 in SPANISH"
tap2 = "STRING OF UI TEST 2 in SPANISH"
}
只需在生成UITest的代码中，更改我们刚刚创建的变量的“字符串”（tap1和tap2）。
就我而言：
let textView = scrollViewsQuery.otherElements.containing(.staticText, identifier:tap1).children(matching: .textView).element
我在使用SWIFT 4。
希望能帮助到你 ：）