我正在尝试使用来自mysql的图像类型作为附件发送电子邮件。它一直给我一个错误警告：file_get_contents（）：/srv/disk18/3303837/www/pommecannelle.lu/encomendas/php/sendmail.php在第41行的文件名不能为空]
Envio emailto --------------------------------------- 数据：
</form>
<?php
if ($_SERVER["REQUEST_METHOD"]=="POST"){
$sel=$_POST["Date"];
require_once 'dbConfig.php';
// Check connection
if (!$mysqli) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT * FROM Encomendas WHERE data='".$sel."'";
$result = mysqli_query($mysqli, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
$msg ='<html><body>';
$msg .= '<p style="color:#080;font-size:18px;">';
$msg .= "Peso: " .$row["peso"]. "<br>";
$msg .= "Massa: " .$row["massa"]. "<br>";
$msg .= "Recheio: " .$row["recheio"] ."<br>";
$msg .= "Cobertura: " .$row["cobertura"] ."<br>";
$msg .= "Obs: " .$row["message"] ."<br>";
$msg .= '</p></body></html>';
$msg = wordwrap($msg,70);
$headers = 'MIME-Version: 1.0' . "\r\n";
$headers .= 'Content-type: text/html; charset=UTF-8'. "\r\n";
$headers .= 'From: pomme <[email protected]>' . "\r\n";
$headers .= '\r\nContent-Type: multipart/mixed;';
ob_start();
$attachment = chunk_split(base64_encode(file_get_contents($row['imagem'])));
if(mail("[email protected]","Encomenda Pomme Cannelle",$msg,$headers)){
echo 'Your mail has been sent successfully.';
} else{
echo 'Unable to send email. Please try again.';
}
}
} else {
echo "0 results";
}
mysqli_close($mysqli);
}
?>
行而言，该列不为空。空[警告：文件获取内容（）：文件名不能为空在第41行 /srv/disk18/3303837/www/pommecannelle.lu/encomendas/php/sendmail.php中
$row['imagem']返回的值为空。检查您的数据库该列是否存在，并且对于[[any
ob_start();
$attachment = false;
if (!empty($row['imagem']) {
$fileContents = file_get_contents($row['imagem']);
if ($fileContents !== FALSE) {
$attachment = chunk_split(base64_encode($fileContents));
}
}
if ($attachment) {
// Now send your email
...
}
我也注意到您从未使用$ attachment做任何事情。
取决于这是否是业余爱好还是大型项目，还应该检查该列是否存在array_key_exists()，并且/或者也要进行错误处理。P.S。 -如果这很重要，请花一点时间来了解SQL Injection