为什么 Apache 返回 200ok 格式错误的应用程序响应，如 b'404 NOT FOUND'

Question

我有一个示例 python 应用程序作为 docker 容器运行并配置了 apache2.4 和 openssl (python-server.py)：

PORT_NUMBER = 80

class myHandler(BaseHTTPRequestHandler):
    def do_GET(self):
        if self.path == "/good":
            self.wfile.write("HTTP/1.0 404 Not Found\r\n\r\nThis is the good page.".encode("utf-8"))
            return
        elif self.path == "/bad":
            self.wfile.write("HTTP/1.0 b'404 Not Found'\r\n\r\nThis is the bad page.".encode("utf-8"))
            return
        self.send_response(404)
        self.send_header('Content-type', 'text/html')
        self.end_headers()
        # Send the html message
        self.wfile.write(
            "Test app to produce good and bad responses\n"
            "For successful 404 response, use /good URL\n"
            "For incorrectly formatted response, use /bad URL\n".encode("utf-8"))
        return

server = HTTPServer(('', PORT_NUMBER), myHandler)
print('Started httpserver on port ', PORT_NUMBER)

结果 以下是我分别看到的 /good 和 /bad 的回复：

curl -ik --cert '<your cert>'  https://<app-host-name>/good  --resolve <app-host-name>:443:<ip>

HTTP/1.1 404 Not Found
Date: Fri, 14 Apr 2023 08:06:14 GMT
Server: Apache/2.4.53 (Unix) OpenSSL/3.0.7+
Transfer-Encoding: chunked

This is the good page.%

curl -ik --cert '<your cert>'  https://<app-host-name>/bad  --resolve <app-host-name>:443:<ip>

HTTP/1.1 200 OK
Date: Fri, 14 Apr 2023 08:18:02 GMT
Server: Apache/2.4.53 (Unix) OpenSSL/3.0.7+
Transfer-Encoding: chunked

HTTP/1.0 b'404 Not Found'
This is the bad page.%

如何配置 apache，使其不会为响应主体格式错误的任何端点返回 200ok？

Apache 应该返回 404 或 500 而不是 200ok