这个问题是关于如何实现范围,用户将在特定级别上获得奖励,一旦他们获得奖励,奖励字段将不再显示他们声称的奖励。例如:
用户在20级,在他的奖励面板上,有3个可用的奖励,10级,15级和20级。因此,如果用户声称10级奖励,它将不再显示在面板上,除了15级和20个奖励。
以下是刀片的代码:
@foreach(App\LevelRewards::getRewards()->get() as $rewards)
@if(Auth::user()->level >= $rewards->level_required || Auth::user()->level == $rewards->level_required)
@if(App\ClaimReward::claimLevel()->get())
<div class="col-lg-2 col-md-3 col-sm-6 col-xs-6" style="margin: 5px 0px;">
<div class="hovereffect">
<a href="#" class="d-block mb-4 h-100">
<input type ="hidden" name="id" value="{{$rewards->id}}"/>
<img class="img-responsive" src="{{asset('rewards_img/'.$rewards->picture)}}" alt="">
</a>
<div class="overlay">
<h2 style="font-size: 14px;">{{$rewards->details}}</h2>
@if($rewards->type == 'physical')
<button type="button" class="btn btn-success btn-sm" data-toggle="modal" data-target="#claimPhysical" data-details="{{$rewards->details}}" data-id="{{$rewards->id}}" data-level="{{$rewards->level_required}}" data-physical="{{$rewards->item_name}}">
CLAIM
</button>
@else
<button type="button" class="btn btn-success btn-sm" data-toggle="modal" data-target="#claimDigital" data-id="{{$rewards->id}}" data-level="{{$rewards->level_required}}" data-physical="{{$rewards->item_name}}">
CLAIM
</button>
@endif
</div>
<div style="background: #2d2d2d; padding: 9px;">
<span class="credits_top">Required Level: <span>{{$rewards->level_required}}</span></span>
<p>{{$rewards->item_name}}</p>
</div>
</div>
@endif
@endif
@endforeach
这是模型ClaimReward模型的代码:
public function scopeClaimLevel2($query)
{
return $query->join('level_rewards','level_rewards.id','=','claim_rewards.reward_id')->select('level_rewards.*');
}
有关此问题的任何链接和信息来源将受到高度赞赏。谢谢。
编辑:我试过;
public function scopeClaimLevel($query)
{
return $query->join('claim_rewards','claim_rewards.reward_id','=','level_rewards.id')->select('level_rewards.*');
}
public function scopeGetRewards($query)
{
return $query
->join('claim_rewards','claim_rewards.reward_id','=','level_rewards.id')
->whereDoesntHave('claimLevel', function (Builder $query) {
$query->where('claim_rewards.status', '=', '0');
})
->select('level_rewards.*');
}
但它说调用未定义的方法Illuminate \ Database \ Query \ Builder :: getRelated()'
添加另一个表,该表将保存用户已声明的奖励,
并在foreach中检查此用户声明的奖励中是否存在此奖励ID,
如果不是这样显示它,如果是,那么跳过它。
该表将包含2个字段:
1)user_id
2)rewards_id
关于上述评论,
并在您编辑所尝试的内容后,
看起来像查询的顺序是错误的...把selectDoesntHave放在select之前,
并按照Laravel文档示例中的说明更改为它的实现。
试试这个:
public function scopeClaimLevel2($query)
{
return $query
->join('claim_rewards','claim_rewards.reward_id','=','level_rewards.id')
->whereDoesntHave('claim_rewards', function (Builder $query) {
$query->where('status', '=', '0');
})
->select('level_rewards.*');
}
编辑:
尝试更改连接,如下所示:https://laravel.com/docs/5.4/queries#joins
构建连接并在其函数中设置如何连接以及status = 0
return $query
->join('claim_rewards', function ($join) {
$join->on('claim_rewards.reward_id', '=', 'level_rewards.id')->where('status', '=', '0');
})
->select('level_rewards.*');