是否可以在sankey图中显示总数?
例如,提琴波纹显示水果> 地方。我想知道有多少水果是喜欢的地方,在地方有多少水果链接。所以像这样。
Mango (3)
Apple (2)
Pineapple (1)
三种水果都与A地相连,所以A地应该是。
(7) Place A
(多1个是因为葡萄)
http:/jsfiddle.netKhrys5c2urqbx
更新。 看来v42默认增加了重量。
看看这个 jsfiddle
编码
data1 = [
['Apple', 'Place A', 1],
['Apple', 'Place A', 1],
['Grape', 'Place A', 1],
['Grape', 'Place B', 2],
['Pineapple', 'Place A', 1],
['Strawberry', 'Place B', 4],
['Mango', 'Place A', 3]
];
var sourceTotals = {};
for (var i = 0; i < data1.length; i++) {
var item = data1[i],
key = item[0];
if (sourceTotals.hasOwnProperty(key)) {
sourceTotals[key] += item[2];
}
else {
sourceTotals[key] = item[2];
}
}
console.log(sourceTotals);
var destTotals = {};
for (var i = 0; i < data1.length; i++) {
var item = data1[i],
key = item[1];
if (destTotals.hasOwnProperty(key)) {
destTotals[key] += item[2];
}
else {
destTotals[key] = item[2];
}
}
console.log(destTotals);
data1.forEach( function(d) {
d[0] = d[0] + " (" + sourceTotals[d[0]] + ")";
d[1] = "(" + destTotals[d[1]] + ") " + d[1];
})
如果你使用d3.js sankey,它会自动求和并显示在工具提示中,就像这个例子......http:/bl.ocks.orgd3noobc9b90689c1438f57d649。
这就解决了当你有多层次的sankey图时的公认答案的问题。
参照原答案计算 "sourceTotals "和 "destTotals"
假设我有一些带有多层次sankey图数据的arr "图表"。
this.chart = {
type: 'Sankey',
title: '',
data: [
[ 'USA', 'Mexico', 15 ],
[ 'USA', 'Brazil', 16 ],
[ 'South America', 'Mexico', 4 ],
[ 'South America', 'Brazil', 4 ],
[ 'Jamaica', 'Mexico', 18 ],
[ 'South Africa', 'Brazil', 2 ],
[ 'England', 'Brazil', 9 ],
[ 'England', 'Mexico', 9 ],
[ 'Mexico', 'Japan', 4 ],
[ 'Mexico', 'North Pole', 4 ],
[ 'China', 'Denmark', 5 ],
[ 'China', 'Canada', 7 ],
[ 'Mexico', 'China', 10 ],
],
}
首先删除出现在sourceTotals对象中的目的键。
for (const key in destTotals) {
if (destTotals.hasOwnProperty(key)) {
if (sourceTotals.hasOwnProperty(key)) {
delete sourceTotals[key];
}
}
}
isKeyInObject(query, object) {
for (const key in object) {
if (object.hasOwnProperty(query)) {
return true;
}
}
return false;
}
this.chart.data.forEach( (d) => {
// Check if d[0] key is in source totals
if (this.isKeyInObject(d[0], sourceTotals)) {
d[0] = d[0] + ' (' + sourceTotals[d[0]] + ')';
}
// check of d[1] key exists in dest totals
if (this.isKeyInObject(d[1], destTotals)) {
d[1] = '(' + destTotals[d[1]] + ') ' + d[1];
}
// deal with destination keys in source index in original arr
// check if key in position 0 of original chart data is available in destTotals object
// change its name to the name key in destTotals
if (this.isKeyInObject(d[0], destTotals)) {
console.log('POS_ZERO_IN_DEST', d[0]);
d[0] = '(' + destTotals[d[0]] + ') ' + d[0];
}
});