public Message getMessageByAuthor(String authorName) {
List<Message> nameList = new ArrayList<Message>(messages.values());
Message message = null;
if (!authorName.isBlank()) {
Iterator<Message> iterator = nameList.iterator();
while (iterator.hasNext()) {
message = iterator.next();
if (message.getMessageAuthor().contains(authorName)) {
return message;
}
}
}
return message;
}
正如Triby在评论中所提到的,您应该创建一个新的List并添加与您的条件匹配的元素,然后返回该列表,以便在匹配时获得多个元素。
public List<Message> getMessageByAuthor(String authorName) {
List<Message> nameList = new ArrayList<Message>(messages.values());
List<Message> responseMessageList = new ArrayList<>();
Message message = null;
if (!authorName.isBlank()) {
Iterator<Message> iterator = nameList.iterator();
while (iterator.hasNext()) {
message = iterator.next();
if (message.getMessageAuthor().contains(authorName)) {
responseMessageList.add(message);
}
}
}
return responseMessageList;
}