我刚开始学习python,然后这个纸牌游戏问世了,我不知道该怎么办。基本上,我需要创建一个for循环,并在其中向用户询问card:。最重要的是,我需要在main()之外定义一个函数,例如def ppcard(card):,然后打印出该卡的“漂亮打印”版本。如果用户放置卡片:4h,则输出应为Spade的4。所以这就是我感到困惑的地方,我尝试了很多次,但是我不知道如何才能完成漂亮的打印。我不知道如何将副牌中的值(例如“ 2s”中的“ s”)匹配到“锹”。
def main():
rank = ['2','3','4','5','6','7','8','9','t','J','Q','K','A']
suit = ['s','h','d','c']
deck = []
card = input('card:')
for i in rank:
for n in suit:
combo = i + n
deck = deck + [combo]
for i in range( len( deck) ):
if card not in deck:
print('Not a card')
continue
if card == 00:
print('Finished!')
break
main()
suits = {s:"Spades",h:"Hearts",d:"Diamonds",c:"Clubs"}
ranks = {2:"2",3:"3",4:"4",5:"5",6:"6",7:"7",8:"8",9:"9",t:"10",J:"Jack",Q:"Queen",K:"King",A:"Ace"}
def ppcard(card):
for i in list(card):
ranks[i] = card[0]
suits[i] = card[1]
print(ranks[i], 'of', suits[i])
ppcard()
您可以将card
中的相应字母用作ranks
和suits
字典的键:
def ppcard(card):
print(ranks[card[0]], 'of', suits[card[1]])