我已经搜索到了可以避免重复错误的插入方法
ref:MySQL: Insert record if not exists in table
INSERT INTO table_listnames (name, address, tele)
SELECT * FROM (SELECT 'Unknown' AS name, 'Unknown' AS address, '022' AS tele) AS tmp
WHERE NOT EXISTS (
SELECT name FROM table_listnames WHERE name = 'Unknown'
) LIMIT 1;
Query OK, 1 row affected (0.00 sec)
Records: 1 Duplicates: 0 Warnings: 0
SELECT * FROM `table_listnames`;
+----+---------+-----------+------+
| id | name | address | tele |
+----+---------+-----------+------+
| 1 | Rupert | Somewhere | 022 |
| 2 | John | Doe | 022 |
| 3 | Unknown | Unknown | 022 |
+----+---------+-----------+------+
是否可以批量处理?或批量添加数据的格式]
ref:insert multiple rows via a php array into mysql
计划集成此一个
$sql = array();
foreach( $data as $row ) {
$sql[] = '("'.mysql_real_escape_string($row['text']).'", '.$row['category_id'].')';
}
mysql_query('INSERT INTO table (text, category) VALUES '.implode(',', $sql));
有办法吗?
我建议为此使用ON DUPLICATE KEY
语法。这将简化查询,并允许使用VALUES()
语句,该语句很方便从应用程序传递参数。
为此,您需要在列name
上使用唯一(或主键)约束。如果不存在,请创建它:
create unique index idx_table_listnames on table_listnames(name);
然后,您可以做:
insert into table_listnames(name, address, tele)
values('Unknown', 'Unknown', '022')
on duplicate key update name = values(name)
冲突子句会在唯一索引上捕获冲突,并执行无操作更新。
附带说明:使用参数化查询将数据从应用程序传递到查询;转义输入不足以使查询安全。