在 MySql 中将列中的所有文本转换为驼峰式大小写

Question

我正在寻找一种方法将我在数据库中的所有文本转换为 Camel Case / Proper Case

即从

CAMEL HAS LEGS

到

Camel Has Legs

我在这里找到一个answer，它要求创建一个函数（如下），然后使用该函数转换文本。

我在共享主机服务器上使用 MySQL 版本：

5.6.32-78.1

。当我执行以下功能时，出现错误

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 3 

如何纠正这个错误？我是 MySQL 的新手

CREATE FUNCTION `proper_case`(str varchar(128)) RETURNS varchar(128)
BEGIN
DECLARE n, pos INT DEFAULT 1;
DECLARE sub, proper VARCHAR(128) DEFAULT '';

if length(trim(str)) > 0 then
    WHILE pos > 0 DO
        set pos = locate(' ',trim(str),n);
        if pos = 0 then
            set sub = lower(trim(substr(trim(str),n)));
        else
            set sub = lower(trim(substr(trim(str),n,pos-n)));
        end if;

        set proper = concat_ws(' ', proper, concat(upper(left(sub,1)),substr(sub,2)));
        set n = pos + 1;
    END WHILE;
end if;

RETURN trim(proper);
END

Answer 1

您需要使用

DELIMITER

语句更改查询分隔符。否则，体内的

;

结束

CREATE FUNCTION

语句。

参见 MySQL 中的定界符

DELIMITER $$

CREATE FUNCTION `proper_case`(str varchar(128)) RETURNS varchar(128)
BEGIN
DECLARE n, pos INT DEFAULT 1;
DECLARE sub, proper VARCHAR(128) DEFAULT '';

if length(trim(str)) > 0 then
    WHILE pos > 0 DO
        set pos = locate(' ',trim(str),n);
        if pos = 0 then
            set sub = lower(trim(substr(trim(str),n)));
        else
            set sub = lower(trim(substr(trim(str),n,pos-n)));
        end if;

        set proper = concat_ws(' ', proper, concat(upper(left(sub,1)),substr(sub,2)));
        set n = pos + 1;
    END WHILE;
end if;

RETURN trim(proper);
END 
$$

DELIMITER ;

Answer 2

concat ( upper(substring(name,1,1)), lower(right(name,length(name)-1)))

Answer 3

table_name = cricket_team
column_name = player_names

select player_names, concat(
  upper(substring(substring_index(player_names,' ',1),1,1)),   
  lower(substring(substring_index(player_names,' ',1),2)) , ' ',
  upper(substring(substring_index(player_names,' ',-1),1,1)),
  lower(substring(substring_index(player_names,' ',-1),2)) 
  ) as casing_player_name
from cricket_team;

Answer 4

最简单的一行答案转换为名称为列的驼峰式大小写：

select CONCAT(UPPER(substr(name,1,1)),LOWER(substr(name,-(length(name)-1),length(name)-1))) name from Users