我有以下型号:
class Model(models.Model):
creator = models.ForeignKey(User,related_name='com_creator',on_delete=models.SET_NULL, blank=True, null=True)
username = models.CharField(max_length=60,default="")
created = models.DateTimeField(auto_now_add=True)
body = models.TextField(max_length=10000,default=" ")
subtype = models.CharField(_("SubType"),max_length=100)
typ = models.CharField(_("Type"),max_length=50)
plus = models.ManyToManyField(User,related_name='com_plus', verbose_name=_('Plus'), blank=True)
is_anonymous = models.BooleanField(_('Stay Anonymous'), blank=True, default=False)
typ和subtype中的值是代码,例如:“6_0_p”,(因为原始值长得可笑,所以我使用代码和字典来翻译为人类可读的形式)。
问题:如何在 django admin 中拦截这些值并将其转换为人类可读的形式?
这是我到目前为止尝试过的:
class ModelAdmin(admin.ModelAdmin):
model = Model
extra = 1
exclude = ("username","creator","plus" )
readonly_fields = ('subtype','typ','is_anonymous','created')
fields = ('body','subtype','typ')
def typ(self, obj):
self.typ = "ppp"
obj.typ = "ppp"
return "pppp"
我尝试返回对象、自身和其他一些值。我还尝试在不使用可调用函数的情况下设置该值,只需声明“typ='xxx'”。没有什么。我可能不明白这整件事是如何运作的......
任何想法将不胜感激。
您需要创建一个与您的方法名称相对应的
readonly_field
,然后从该方法返回任何内容。
class MyAdmin(admin.ModelAdmin):
readonly_fields = ('my_custom_field',)
def my_custom_field(self, obj):
return 'Return Anything Here'
我认为您的代码不起作用,因为 method 名称与字段相同。
您必须更改字段的名称,例如字段元组中的 _typ,然后添加一个名为 _typ 的方法,该方法返回任何内容或某些 obj attr。
即:
class ModelAdmin(admin.ModelAdmin):
model = Model
extra = 1
exclude = ("username","creator","plus" )
readonly_fields = ('subtype','typ','is_anonymous','created')
fields = ('body','subtype','_typ')
def _typ(self, obj):
return "pppp"
在 Django 4 及更高版本中,您可以轻松添加自定义(只读)字段,如下所示:
class FooAdmin(admin.ModelAdminAbstractAdmin):
readonly_fields = [
'_dynamic_field',
]
fieldsets = [
('Form', {
'fields': (
'_dynamic_field',
),
'classes': ('form-group',)
}),
]
def _dynamic_field(self, obj=None):
if obj is not None:
return 'Bar'
return "Foo"
# to change the label
_dynamic_field.__name__ = "Dynamic field label"
如您所见,该字段也需要位于
readonly_fields
和 fieldsets
中。
choices
允许这样做。它们是https://docs.djangoproject.com/en/5.0/ref/models/fields/#choices:
采用下面描述的格式的映射或迭代,用作该字段的选择。如果给出选择,它们将通过模型验证强制执行,并且默认表单小部件将是包含这些选项的选择框,而不是标准文本字段。
如果给出了映射[或可迭代],则键[或第一个]元素是要在模型上设置的实际值,第二个元素是人类可读的名称。
适应 https://docs.djangoproject.com/en/5.0/ref/models/fields/#enumeration-types 适应您的问题:
class Model(models.Model):
class MyTypes(models.TextChoices):
T6_0_P = '6_0_p', 'original value that is ridiculously long'
T6_0_Q = '6_0_q', 'other original value that is ridiculously long'
T7_0_P = '7_0_p', 'yet another original value that is ridiculously long'
class MySubTypes(models.TextChoices):
ST6_0_P = 's6_0_p', 'original value that is ridiculously long'
ST6_0_Q = 's6_0_q', 'other original value that is ridiculously long'
ST7_0_P = 's7_0_p', 'yet another original value that is ridiculously long'
creator = models.ForeignKey(
User, related_name='com_creator',on_delete=models.SET_NULL, blank=True, null=True
)
username = models.CharField(max_length=60, default="")
created = models.DateTimeField(auto_now_add=True)
body = models.TextField(max_length=10000, default=" ")
subtype = models.CharField(_("SubType"), choices=MySubTypes, max_length=100)
typ = models.CharField(_("Type"), choices=MyTypes, max_length=50)
plus = models.ManyToManyField(
User,related_name='com_plus', verbose_name=_('Plus'), blank=True
)
is_anonymous = models.BooleanField(_('Stay Anonymous'), blank=True, default=False)