我从api收到的响应采用以下格式：
"NetRange: 185.0.0.0 - 185.255.255.255 CIDR: 185.0.0.0/8 NetName: RIPE-185 NetHandle: NET-185-0-0-0-1 Parent: () NetType: Allocated to RIPE NCC OriginAS: Organization: RIPE Network Coordination Centre (RIPE) RegDate: 2011-01-04 Updated: 2011-02-08 Comment: These addresses have been further assigned to users in Comment: the RIPE NCC region. Contact information can be found in Comment: the RIPE database at http://www.ripe.net/whois Ref: https://rdap.arin.net/registry/ip/185.0.0.0 ResourceLink: https://apps.db.ripe.net/search/query.html ResourceLink: whois.ripe.net **OrgName: RIPE Network Coordination Centre** OrgId: RIPE Address: P.O. Box 10096 City: Amsterdam StateProv: PostalCode: 1001EB Country: NL RegDate: Updated: 2013-07-29 Ref: https://rdap.arin.net/registry/entity/RIPE ReferralServe "
但是我只需要突出显示值对。在python中应该如何完全格式化？我正在使用python 3。
您可以使用re正则表达式模块执行此操作：
re这是获取的数据的简单解析器：
import re
#assume that resp is response from API
resp = "NetRange: 185.0.0.0 - 185.255.255.255 CIDR: 185.0.0.0/8 NetName: RIPE-185 NetHandle: NET-185-0-0-0-1 Parent: () NetType: Allocated to RIPE NCC OriginAS: Organization: RIPE Network Coordination Centre (RIPE) RegDate: 2011-01-04 Updated: 2011-02-08 Comment: These addresses have been further assigned to users in Comment: the RIPE NCC region. Contact information can be found in Comment: the RIPE database at http://www.ripe.net/whois Ref: https://rdap.arin.net/registry/ip/185.0.0.0 ResourceLink: https://apps.db.ripe.net/search/query.html ResourceLink: whois.ripe.net OrgName: RIPE Network Coordination Centre OrgId: RIPE Address: P.O. Box 10096 City: Amsterdam StateProv: PostalCode: 1001EB Country: NL RegDate: Updated: 2013-07-29 Ref: https://rdap.arin.net/registry/entity/RIPE ReferralServe "
regex = r"OrgName:\s(.+?)\sOrgId"
orgName = re.findall(regex, resp)[0]
print(orgName) #RIPE Network Coordination Centre