我想创建一个猜词游戏,这些单词会有答案。我怎样才能控制随机单词的含义而不是这个?
val list = listOf("one", "two", "three", "four", "five")
val key = listOf("onek", "twok", "threek", "fourk", "fivek")
if(binding.randomWord.text == list[0]) {
binding.wordMeaning.text = key[0]
}
if(binding.randomWord.text == list[1]) {
binding.wordMeaning.text = key[1]
}
if(binding.randomWord.text == list[2]) {
binding.wordMeaning.text = key[2]
}
if(binding.randomWord.text == list[3]) {
binding.wordMeaning.text = key[3]
}
if(binding.randomWord.text == list[4]) {
binding.wordMeaning.text = key[4]
}
我想学习这个方法的另一种方式。
您可以使用
for
循环。在 Kotlin 中,它会是这样的:
for (idx in list.indices) {
if(binding.randomWord.text == list[idx]) {
binding.wordMeaning.text = key[idx]
}
}
只需确保数组的长度始终相同,否则会得到错误的结果。