我如何根据状态更改按钮颜色（绿色表示“接受”，红色表示“删除”）

Answer 1

数据库状态默认为pending

我在代码中没有看到

status

属性，但显示状态为待处理的纯字符串

<span class="mj_btn btn btn-warning">pending</span>
<!-- while it suppose to be -->
<span class="mj_btn btn btn-warning">{{ $show->status }}</span>

假设它确实存在，你可以做

<td>
@if ($show->status === 'Accept')
    <span class="mj_btn btn btn-green">Accepted</span>
@elseif ($show->status === 'Delete')
    <span class="mj_btn btn btn-danger">Deleted</span>
@else
    <span class="mj_btn btn btn-warning">Pending</span>
@endif
</td>

参见：https://laravel.com/docs/5.1/blade#displaying-data

Answer 2

    <td>
                                @if ($show->jobstatus === "Accepted")
                                    <span class="mj_btn btn btn-success">Accepted</span>
                                @elseif ($show->jobstatus === "Rejected")
                                    <span class="mj_btn btn btn-danger">Rejected</span>
                                @else
                                    <span class="mj_btn btn btn-warning">Pending</span>
                                @endif
                            </td>

Answer 3

或者当你使用

1.

laravel esialy customaize this code nad add automatic refresh in the
    page to more interactive 
       
            

   @php
                   if($da->status == "requested") {
                   echo "<td><button class='btn btn-primary'>Requested</button></td>";
                   } else {
                   echo "<td><button class='btn btn-success'>Ordered</button></td>";
                   }
                   @endphp