对4.6中的所有新增内容感到非常兴奋!在回顾了大部分的变化后,我没有看到AKMIDICallbackInstrument
有任何明显的不同,但是,我再也无法接到回电。这是我的实现:
var sequencer: AKSequencer = AKSequencer()
var callbackTrack: AKMusicTrack = AKMusicTrack()
var callbackInst: AKMIDICallbackInstrument = AKMIDICallbackInstrument()
---
public func setupSequencerWithBeats(beats: Int, bpm: Double) {
print("Num beats: \(beats) | BPM: \(bpm)")
sequencer.setTempo(bpm)
callbackTrack = sequencer.newTrack()!
callbackTrack.setMIDIOutput(callbackInst.midiIn)
for i in 0 ..< beats {
callbackTrack.add(noteNumber: MIDINoteNumber(60), velocity: 100, position: AKDuration(beats: Double(i)), duration: AKDuration(beats: 1))
}
callbackInst.callback = {status, noteNumber, velocity in
//Using the new AKMIDIStatus object to unwrap the status and check if it's .noteOn
if let midiStatus = AKMIDIStatus(byte: status), midiStatus.type != .noteOn
{
return
}
// just some delegates to other classes
self.sequencerdDelegate?.didRecieveCallbackFromSequencer(beatNumber: self.beatNumber)
self.beatNumber += 1
}
当我打电话给sequencer.play()
时,callbackInst
无法再发起回调。我在这里的假设是用setMIDIOutput()
方法改变了一些东西?如果在我的音序器中触发.noteOn事件时有更好的方法来获取回调,我很想知道。感谢大家!
感谢AudioKit贡献者oettam看到了影响所有MIDI组件的4.6.0中的一个非常小的变化!这个问题已通过4.6.1修复!他的承诺:https://github.com/AudioKit/AudioKit/commit/dcfbbb98058425e43af23b9df69fd9794ecc34d5