有 gridView,其中有一些图像。 gridView 的单元格来自相同的预定义布局,具有相同的 id 和 desc。
R.id.item_image == 2131493330
onView(withId(is(R.id.item_image))).perform(click());
由于网格中的所有单元格都有相同的 id,所以它得到了
AmbiguousViewMatcherException
。
如何只选择第一个或其中任何一个?
谢谢!
android.support.test.espresso.AmbigouslyViewMatcherException:“with id: is <2131493330>”匹配层次结构中的多个视图。 问题视图在下面标有“****匹配****”。
+------------->ImageView{id=2131493330, res-name=item_image, desc=图像, 可见性=VISIBLE, 宽度=262, 高度=262, has-focus=false, has-focusable = false,has-window-focus = true,is-clickable = false,is-enabled = true,is-focused = false,is-focusable = false,is-layout-requested = false,is-selected = false,root-is-layout-requested=false,has-input-connection=false,x=0.0,y=0.0} ****匹配****
+------------->ImageView{id=2131493330, res-name=item_image, desc=图像, 可见性=VISIBLE, 宽度=262, 高度=262, has-focus=false, has-focusable = false,has-window-focus = true,is-clickable = false,is-enabled = true,is-focused = false,is-focusable = false,is-layout-requested = false,is-selected = false,root-is-layout-requested=false,has-input-connection=false,x=0.0,y=0.0} ****匹配**** |
编辑:有人在评论中提到withParentIndex现在可用,请在使用下面的自定义解决方案之前先尝试一下。
令我惊讶的是,我无法通过简单地提供索引和匹配器(即 withText、withId)来找到解决方案。当您处理 onData 和 ListViews 时,接受的答案只能解决问题。
如果屏幕上有多个具有相同 resId/text/contentDesc 的视图,您可以使用此自定义匹配器选择所需的视图,而不会导致 AmbigouslyViewMatcherException:
public static Matcher<View> withIndex(final Matcher<View> matcher, final int index) {
return new TypeSafeMatcher<View>() {
int currentIndex = 0;
@Override
public void describeTo(Description description) {
description.appendText("with index: ");
description.appendValue(index);
matcher.describeTo(description);
}
@Override
public boolean matchesSafely(View view) {
return matcher.matches(view) && currentIndex++ == index;
}
};
}
例如:
onView(withIndex(withId(R.id.my_view), 2)).perform(click());
将对 R.id.my_view 的第三个实例执行单击操作。
与网格视图情况不完全相关,但您可以使用 hamcrest
allOf
匹配器来组合多个条件:
import static org.hamcrest.CoreMatchers.allOf;
onView(allOf(withId(R.id.login_password),
withEffectiveVisibility(ViewMatchers.Visibility.VISIBLE)))
.check(matches(isCompletelyDisplayed()))
.check(matches(withHint(R.string.password_placeholder)));
您应该使用
onData()
来对GridView
进行操作:
onData(withId(R.id.item_image))
.inAdapterView(withId(R.id.grid_adapter_id))
.atPosition(0)
.perform(click());
此代码将单击
GridView
中第一项内的图像
尝试过@FrostRocket 的答案,看起来最有希望,但需要添加一些自定义:
public static Matcher<View> withIndex(final Matcher<View> matcher, final int index) {
return new TypeSafeMatcher<View>() {
int currentIndex;
int viewObjHash;
@SuppressLint("DefaultLocale") @Override
public void describeTo(Description description) {
description.appendText(String.format("with index: %d ", index));
matcher.describeTo(description);
}
@Override
public boolean matchesSafely(View view) {
if (matcher.matches(view) && currentIndex++ == index) {
viewObjHash = view.hashCode();
}
return view.hashCode() == viewObjHash;
}
};
}
我创建了一个 ViewMatcher 来匹配它找到的第一个视图。 也许这对某人有帮助。 例如。当你没有 AdapterView 来使用 onData() 时。
/**
* Created by stost on 15.05.14.
* Matches any view. But only on first match()-call.
*/
public class FirstViewMatcher extends BaseMatcher<View> {
public static boolean matchedBefore = false;
public FirstViewMatcher() {
matchedBefore = false;
}
@Override
public boolean matches(Object o) {
if (matchedBefore) {
return false;
} else {
matchedBefore = true;
return true;
}
}
@Override
public void describeTo(Description description) {
description.appendText(" is the first view that comes along ");
}
@Factory
public static <T> Matcher<View> firstView() {
return new FirstViewMatcher();
}
}
像这样使用它:
onView(FirstViewMatcher.firstView()).perform(click());
案例:
onView( withId( R.id.songListView ) ).perform( RealmRecyclerViewActions.scrollTo( Matchers.first(Matchers.withTextLabeled( "Love Song"))) );
onView( Matchers.first(withText( "Love Song")) ).perform( click() );
在我的 Matchers.class 中
public static Matcher<View> first(Matcher<View> expected ){
return new TypeSafeMatcher<View>() {
private boolean first = false;
@Override
protected boolean matchesSafely(View item) {
if( expected.matches(item) && !first ){
return first = true;
}
return false;
}
@Override
public void describeTo(Description description) {
description.appendText("Matcher.first( " + expected.toString() + " )" );
}
};
}
通过单击不同位置的相同 ID 视图,会为它们生成不同的代码,因此请尝试一下。
它实际上解决了这些问题。
class NthMatcher internal constructor(private val id: Int, private val n: Int) : TypeSafeMatcher<View>(View::class.java) {
companion object {
var matchCount: Int = 0
}
init {
var matchCount = 0
}
private var resources: Resources? = null
override fun describeTo(description: Description) {
var idDescription = Integer.toString(id)
if (resources != null) {
try {
idDescription = resources!!.getResourceName(id)
} catch (e: Resources.NotFoundException) {
// No big deal, will just use the int value.
idDescription = String.format("%s (resource name not found)", id)
}
}
description.appendText("with id: $idDescription")
}
public override fun matchesSafely(view: View): Boolean {
resources = view.resources
if (id == view.id) {
matchCount++
if(matchCount == n) {
return true
}
}
return false
}
}
这样声明:
fun withNthId(resId: Int, n: Int) = CustomMatchers.NthMatcher(resId, n)
并像这样使用:
onView(withNthId(R.id.textview, 1)).perform(click())
https://github.com/agoda-com/Kakao/issues/90:
class InputScreen : Screen<InputScreen>() {
fun inputLayout(lambda: KEditText.() -> Unit) =
KEditText { withIndex(0, { withId(R.id.input_layout) }) }.invoke(lambda)
}
onView(allOf(withId(R.id.tvYourName),isDescendantOfA(withId(R.id.inParentName)))).perform(click())