通过截击访问URL的问题

Question

我正在尝试通过网址获取json。当我尝试通过我的导航器访问URL时，它工作正常。但是，当我尝试通过凌空访问它时，出现此错误：

02-26 17:07:57.706 15056-15125/com.perso.simon.ulr_geoloc E/Volley: [5254] BasicNetwork.performRequest: Unexpected response code 403 for ...
02-26 17:07:57.716 15056-15125/com.perso.simon.ulr_geoloc E/Volley: [5254] BasicNetwork.performRequest: Unexpected response code 403 for ...
02-26 17:07:57.719 15056-15056/com.perso.simon.ulr_geoloc E/error: com.android.volley.AuthFailureError

我看不到错误可能在哪里。

这是我的代码：

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_splash_screen);

    if(!isConnectedInternet(SplashScreenActivity.this)) {
        AlertDialog.Builder builder = new AlertDialog.Builder(SplashScreenActivity.this);

        builder.setPositiveButton(R.string.dialog_box_confirmation, new DialogInterface.OnClickListener() {
            @Override
            public void onClick(DialogInterface dialog, int which) {
                Intent i = new Intent(SplashScreenActivity.this, SplashScreenActivity.class);
                startActivity(i);
            }
        });

        builder.setMessage(R.string.dialog_box_text).setTitle(R.string.dialog_box_title);

        AlertDialog dialog = builder.create();
        dialog.show();
    } else {
        StringRequest requestBat = new StringRequest(urlBat, new Response.Listener<String>() {
            @Override
            public void onResponse(String response) {
                Log.e("test", response);
            }
        }, new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError error) {
                Log.e("error", error.toString());
            }
        });

        requestBat.setRetryPolicy(new DefaultRetryPolicy(10000, DefaultRetryPolicy.DEFAULT_MAX_RETRIES, DefaultRetryPolicy.DEFAULT_BACKOFF_MULT));

        final RequestQueue requestQueue = Volley.newRequestQueue(SplashScreenActivity.this);
        requestQueue.add(requestBat);
    }
}

Answer 1

在您的问题中，您说：'我正在尝试通过网址获取json'但是在您的代码中，您会输入'StringRequest'。我认为如果您将StringRequest更改为JsonRequest问题即可解决。