页面未找到,URL未解析

问题描述 投票:0回答:1

我试图通过在网络浏览器中粘贴网址http://127.0.0.1:8000/upload_results/UniEX_HG1_A15来调用我的views.py中的函数,但请求失败,我无法理解为什么我的网址模式不起作用。

错误:

Page not found (404)
Request Method:     GET
Request URL:    http://127.0.0.1:8000/upload_results/UniEX_HG1_A15

Using the URLconf defined in varview.urls, Django tried these URL patterns, in this order:

    ^$ [name='show_index']
    ^admin/
    ^upload/ [name='varview_submission']
    ^upload_results/(?P<project_id>[0-9A-Za-z_]+)/ [name='varview_upload_results']
    ^validate/(?P<project_id>[0-9A-Za-z_]+)/ [name='varview_validate']
    ^filterallprojects/[0-9A-Za-z_]+ [name='varview_filterallprojects']
    ^project/(?P<project_id>[0-9A-Za-z_]+)/wgsmetrics/ [name='varview_wgsmetrics']
    ^project/(?P<project_id>[0-9A-Za-z_]+)/targetgenecoverage/ [name='varview_targetgenecoverage']
    ^project/(?P<project_id>[0-9A-Za-z_]+)/(?P<display_option>[0-9A-Za-z_]+)/ [name='varview_project']
    ^media\/(?P<path>.*)$

The current path, upload_results/UniEX_HG1_A15, didn't match any of these.

这是我的urls.py:

from django.conf import settings
from django.conf.urls import url
from django.conf.urls.static import static
from django.contrib import admin
from varview import views
from varview.forms import DataUploaderForm1, DataUploaderForm2, GetProjectIdForm

urlpatterns = [
    url(r'^$', views.show_index, name='show_index'),
    url(r'^admin/', admin.site.urls),
    url(r'^upload/', views.init_submission, name='varview_submission'),
    url(r'^upload_results/(?P<project_id>[0-9A-Za-z_]+)/', views.upload_results, name='varview_upload_results'), 
]

这已经有一段时间了,但与此同时我做了很多改变。最新的变化包括芹菜(djcelery)。索引页面和其他页面仍然有效。我已经阅读了许多与django-url相关的帖子,但无法理解。

谢谢您的帮助。

django django-urls django-2.1
1个回答
1
投票

请注意您的网址有一个尾部斜杠,

^upload_results/(?P<project_id>[0-9A-Za-z_]+)/

但是您尝试访问没有尾部斜杠的URL

/upload_results/UniEX_HG1_A15

通常,Django将重定向到带有斜杠的URL。也许你的MIDDLEWARE设置不正确,或者你已经将APPEND_SLASH设置为False

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