对于Java来说相对较新,所以我不知道问题是什么。在此类的getter设置中,我试图评估输入的整数是1、2还是3,然后它将返回此处描述的先前保存的setter之一。我在setter中使用了相同的条件语句,但是getter告诉我,我的方法需要返回int类型。我究竟做错了什么?还是我应该以一种完全不同的方式来做这件事?大声笑。
public class AssignmentMarks {
private String courseName;
private int assignment1 = 0, assignment2 = 0, assignment3 = 0;
public AssignmentMarks(String name, int mark1, int mark2, int mark3){
//create constructor to use variables.
this.courseName = name;
this.assignment1 = mark1;
this.assignment2 = mark2;
this.assignment3 = mark3;
}
public void setMark(int assignmentNumber, int mark) {
//assign value of the assignments
if(assignmentNumber == 1) {
mark = this.assignment1;
}else if(assignmentNumber == 2) {
mark = this.assignment2;
}else if(assignmentNumber == 3){
mark = this.assignment3;
}
}
public int getMark(int assignmentNum) {
if(assignmentNum == 1) {
return assignment1;
}else if (assignmentNum == 2) {
return assignment2;
} else if (assignmentNum == 3) {
return assignment3;
}
}
}
public int getMark(int assignmentNum) {
if(assignmentNum == 1) {
return assignment1;
}else if (assignmentNum == 2) {
return assignment2;
} else if (assignmentNum == 3) {
return assignment3;
}
// in another case
throw new Exception("Assignment must be 1, 2 or 3);
}
对于二传手
public void setMark(int assignmentNumber, int mark) {
//assign value of the assignments
if(assignmentNumber == 1) {
// BAD mark = this.assignment1; don't set parameter is useless
this.assignment1=mark;
}else if(assignmentNumber == 2) {
// BAD mark = this.assignment2;
this.assignment2=mark;
}else if(assignmentNumber == 3){
// BAD mark = this.assignment3;
this.assignment3=mark;
}
// in another case
throw new Exception("Assignment must be 1, 2 or 3");
}
我不记得您是否必须导入Exception才能抛出它们。如果是,则在代码上方放置import java.lang.Exception
。
您的逻辑可以使用数组来改善,但让我们开始吧,在您运行之后...