Java中的基本加密算法不解密

问题描述 投票:0回答:1

我正在尝试用Java实现TEA(微加密算法)来编码包含大小为512的音频的byte[]

这是我的加密功能:

//Encrypt 64bit/8byte buffer with 128bit/16byte key
public byte[] encrypt(int[] data, int[] key) { 
    int x = data[0]; 
    int y = data[1]; 
    ByteBuffer encrypted = ByteBuffer.allocate(8);
    int sum = 0; 
    int constant = 0x9e3779b9; //magic constant

    for (int k = 0; k < 32; ++k) { 
        sum += constant; 
        x += (y << 4 & 0xfffffff0) + key[0] ^ y + sum ^ (y >> 5 & 0x7ffffff) + key[1]; 
        y += (x << 4 & 0xfffffff0) + key[2] ^ x + sum ^ (x >> 5 & 0x7ffffff) + key[3]; 
    }
    encrypted.putInt(x);
    encrypted.putInt(y);
    return encrypted.array();
}

并解密:

public byte[] decrypt(int[] data, int[] key) { 
    int x = data[0]; 
    int y = data[1]; 
    ByteBuffer decrypted = ByteBuffer.allocate(8);
    int sum = 0xC6EF3720; //32*delta
    int constant = 0x9e3779b9; //magic constant

    for (int k = 0; k < 32; ++k) { 
        x -= (x << 4 & 0xfffffff0) + key[2] ^ x + sum ^ (x >> 5 & 0x7ffffff) + key[3]; 
        y -= (y << 4 & 0xfffffff0) + key[0] ^ y + sum ^ (y >> 5 & 0x7ffffff) + key[1]; 
        sum -= constant; 
    }
    decrypted.putInt(x); 
    decrypted.putInt(y);
    return decrypted.array();
}

和我的加密电话:

ByteBuffer unwrapEncrypt = ByteBuffer.allocate(512);
int[] encryptionKey = {55555, 8888, 123857, 912029};

//block is a byte[] with length 512
ByteBuffer plainText = ByteBuffer.wrap(block);
for (int j = 0; j < block.length / 8; j++) {
    //Initiate array for int pairs
    int[] plainTextInts = new int[2];
    plainTextInts[0] = plainText.getInt();
    plainTextInts[1] = plainText.getInt();
    //Encrypt and store
    unwrapEncrypt.put(encrypt(plainTextInts, encryptionKey));
}

和解密电话:

ByteBuffer audioToPlay = ByteBuffer.allocate(512);
int[] decryptionKey = {55555, 8888, 123857, 912029};

//audio is a byte[] with length 512
ByteBuffer cipherText = ByteBuffer.wrap(audio);
for (int j = 0; j < audio.length / 8; j++) {
    int[] plainTextInts = new int[2];
    //Initiate array for int pairs
    plainTextInts[0] = cipherText.getInt();
    plainTextInts[1] = cipherText.getInt();
    //Decrypt and store
    audioToPlay.put(decrypt(plainTextInts, decryptionKey));
}

很抱歉代码很多 - 我已经尝试过分析发送的音频并收到解密数据 - 它们都是正确的长度,完全不同。如果我删除这4个代码块,音频是完美的。有谁能发现什么了?谢谢

java encryption
1个回答
1
投票

我将decrpyt()方法与Wikipedia' s description of TEA进行比较时似乎有一个错误。你必须在-=运算符的左边交换x和y。以下似乎对我有用:

public byte[] decrypt(int[] data, int[] key) { 
    int x = data[0]; 
    int y = data[1]; 
    ByteBuffer decrypted = ByteBuffer.allocate(8);
    int sum = 0xC6EF3720; //32*delta
    int constant = 0x9e3779b9; //magic constant

    for (int k = 0; k < 32; ++k) { 
        y -= (x << 4 & 0xfffffff0) + key[2] ^ x + sum ^ (x >> 5 & 0x7ffffff) + key[3]; 
        x -= (y << 4 & 0xfffffff0) + key[0] ^ y + sum ^ (y >> 5 & 0x7ffffff) + key[1]; 
        sum -= constant; 
    }
    decrypted.putInt(x); 
    decrypted.putInt(y);
    return decrypted.array();
}
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