对MS Access中的每个查询结果运行子查询

Question

我目前正在PHP应用程序中使用此SQL，并且需要转换为MS Access。

我需要针对第一个结果的第二个查询运行第二个查询，以得出第一场比赛的骑手人数。 （摩托车比赛）

使用PHP非常简单（如果需要，我可以提供完整的代码）

不太清楚如何从Access开始。 （这两种查询在Access中都可以正常工作，只是无法按照我的需要将它们加入）

查询1：

SELECT schedule2.Date, riders.ridername, results.finish, results.points, classes.class, seasons.season
FROM schedule2 RIGHT JOIN (classes RIGHT JOIN ((riders RIGHT JOIN results ON riders.id = results.rider_id) LEFT JOIN seasons ON results.season_id = seasons.id) ON classes.id = results.class_id) ON schedule2.id = results.schedule_id
GROUP BY schedule2.Date, riders.ridername, results.finish, results.points, classes.class, seasons.season, schedule2.id, results.class_id, riders.id
HAVING (((riders.id)=[:id]))
ORDER BY schedule2.Date;

查询2：

SELECT DISTINCT Count(results.rider_id) AS CountOfrider_id
FROM seasons RIGHT JOIN (results LEFT JOIN schedule2 ON results.schedule_id = schedule2.id) ON seasons.id = schedule2.season_id
GROUP BY schedule2.id, results.class_id
HAVING (((schedule2.id)=[:scheduleId]) AND ((results.class_id)=[:classId]));

当前的PHP应用程序生成此结果集：（使用表格选择车手ID）

原始PHP（供参考）

            $getRiderInfo = $dbh->prepare('
                    SELECT riders.ridername, 
                          schedule2.date, 
                          schedule2.id AS scheduleId, 
                          results.class_id AS classId, 
                          results.finish, 
                          results.points, 
                          classes.class, 
                          seasons.season, 
                          riders.id 
                    FROM schedule2 
                    RIGHT JOIN (classes 
                                RIGHT JOIN ((riders 
                                             RIGHT JOIN results 
                                             ON riders.id = results.rider_id) 
                    LEFT JOIN seasons 
                      ON results.season_id = seasons.id) 
                      ON classes.id = results.class_id) 
                      ON schedule2.id = results.schedule_id
                    GROUP BY riders.ridername, 
                             schedule2.date, 
                             classes.class, 
                             seasons.season
                    HAVING (((riders.id)=:id))
                    ORDER BY schedule2.date ASC;
            ');
            $getRiderInfo->bindValue('id', $racer_id);
            if ($getRiderInfo->execute()) {
                while ($iRows = $getRiderInfo->fetch(PDO::FETCH_ASSOC)) {
                    $getCounts = $dbh->prepare('
                            SELECT DISTINCT COUNT(results.rider_id) AS CountOfrider_id,
                                   schedule2.id,
                                   results.class_id
                            FROM seasons
                            RIGHT JOIN(results
                            LEFT JOIN schedule2
                            ON results.schedule_id = schedule2.id) 
                            ON seasons.id = schedule2.season_id
                            GROUP BY schedule2.id , 
                                     results.class_id
                            HAVING (((schedule2.id) = :scheduleId)
                            AND ((results.class_id) = :classId));
                    ');
                    $getCounts->bindValue('scheduleId', $iRows['scheduleId']);
                    $getCounts->bindValue('classId', $iRows['classId']);
                    if ($getCounts->execute()) {
                        while ($iRows1 = $getCounts->fetch(PDO::FETCH_ASSOC)) {
                            $iCount = $iRows1['CountOfrider_id'];
                        }
                    }
                    $iDate = date_create($iRows['date']);
                    echo '<tr><td>' . $iRows['ridername'] . '</td>';
                    echo '<td>' . date_format($iDate, 'm/d/Y') . '</td>';
                    echo '<td>' . $iRows['finish'] . '</td>';
                    echo '<td>' . $iRows['points'] . '</td>';
                    echo '<td>' . $iRows['class'] . '</td>';
                    echo '<td>' . $iRows['season'] . '</td>';
                    echo '<td>' . $iCount . '</td></tr>';
                }
            }

Answer 1

我找到了解决此问题的更好方法。其实我有点想事情。

此数据集永远不会改变，因此，实际上不需要第二个查询，只需运行一次即可创建一个表，该表具有我要查找的第6列的总计数，并向第一个查询添加了另一个联接。 （已经有太多的连接要跟踪。）

它出于我的目的。