如何从包含其他逗号的字符串中的数值中删除逗号？

Question

我正在使用包含帐户声明的数组。我希望能够从数值中删除逗号，以便能够在不丢失重要值的情况下使用逗号进行爆炸。

例如，我的数组包含如下索引：

26 => 20/08/2099,"ATM CASH WITHDRAWAL (ON-US) ATM CASH WITHDRAWAL (ON-US) EMPEMOM, LAGA ATM 2 LOGO NG 000360585490","",20/08/2018,"5,000","","1,316.01"

27 => 27/08/2027,BANK CHARGE 26 SMS CHARGE AND VAT FOR 27TH JUL - 23RD AUG 2018,2803064 028,27/08/2018,109.2,"","1,206.81"

我想删除“5,000”和其他货币值中的逗号，而不删除每个字符串之间的逗号，以便输出看起来像：

26 => 20/08/2099,"ATM CASH WITHDRAWAL (ON-US) ATM CASH WITHDRAWAL (ON-US) EMPEMOM, LAGA ATM 2 LOGO NG 000360585490","",20/08/2018,"5000","","1316.01"

27 => 27/08/2027,BANK CHARGE 26 SMS CHARGE AND VAT FOR 27TH JUL - 23RD AUG 2018,2803064 028,27/08/2018,109.2,"","1206.81"

Answer 1

你也可以使用array_map和preg_replace_callback作为你可以使用的模式：

"\d{1,3}(?:,\d{3})+\.\d{2}"

• "\d{1,3}匹配"，然后是1-3位数
• (?:,\d{3})!重复1次以上的逗号和3位数字
• \.\d{2}"匹配一个点和2位数字，然后是"

Regex demo | Php demo

在preg_replace_callback的回调中，用空字符串替换逗号并返回匹配。

例如：

$atm = array(
    '26' => '20/08/2099,"ATM CASH WITHDRAWAL (ON-US) ATM CASH WITHDRAWAL (ON-US) EMPEMOM, LAGA ATM 2 LOGO NG 000360585490","",20/08/2018,"5,000","","1,316.01"',
    '27' => '27/08/2027,BANK CHARGE 26 SMS CHARGE AND VAT FOR 27TH JUL - 23RD AUG 2018,2803064 028,27/08/2018,109.2,"","1,206.81"'
);

$atm = array_map(function($x) {
    return preg_replace_callback('/"\d{1,3}(?:,\d{3})+\.\d{2}"/', function($m) {
       return  str_replace(',', '', $m[0]);
    }, $x);
}, $atm);

print_r($atm);

结果：

Array
(
    [26] => 20/08/2099,"ATM CASH WITHDRAWAL (ON-US) ATM CASH WITHDRAWAL (ON-US) EMPEMOM, LAGA ATM 2 LOGO NG 000360585490","",20/08/2018,"5,000","","1316.01"
    [27] => 27/08/2027,BANK CHARGE 26 SMS CHARGE AND VAT FOR 27TH JUL - 23RD AUG 2018,2803064 028,27/08/2018,109.2,"","1206.81"
)

Answer 2

你可以使用foreach你的数组并用逗号爆炸然后替换“，”每个数组然后检查它是否是数字

foreach数组然后用逗号分解字符串

$stringArray=explode(",",$str)

然后将每个$ stringArray替换为“，”

$CheckNumber= str_replace(',', '', $string);

并检查它是否是数字：

if (is_numeric($CheckNumber))
   $stringArray[i]=$CheckNumber;

在结束连接数组

join(",",$stringArray);