散列数组，如何计算具有最独特“页面”视图的“网页”列表？

Question

我试图按顺序显示最独特的网页浏览量，但不确定如何显示。我有数据变量：

data = [{"help_page/1"=>"126.318.035.038"},
 {"contact"=>"184.123.665.067"},
 {"home"=>"184.123.665.067"},
 {"about/2"=>"444.701.448.104"},
 {"help_page/1"=>"929.398.951.889"},
 {"index"=>"444.701.448.104"},
 {"help_page/1"=>"722.247.931.582"},
 {"about"=>"061.945.150.735"},
 {"help_page/1"=>"646.865.545.408"},
 {"home"=>"235.313.352.950"},
 {"help_page/1"=>"543.910.244.929"},
 {"home"=>"316.433.849.805"},
 {"contact"=>"543.910.244.929"}]

我尝试过这样的事情：

data.sort_by {|k, v| -v.uniq.count}.collect{|k, v| "#{k}\t#{v.uniq.count} #{'unique views', v.uniq.count}"}

我正在尝试获得与以下内容类似的结果：

/help_page/1    XX unique views
/contact    XX unique views
/home   XX unique views
/index  XX unique views
/about/2    XX unique views
/about  XX unique views

但没有成功。

Answer 1

Enumerable#group_by是您的朋友，下面的所有内容都只是格式化输出。

data.group_by do |h|
  h.to_a.first.first
end.map do |k, v|
  [k, v.count]
end.sort_by(&:last).reverse.to_h
#⇒ {"help_page/1"=>5,
#   "home"=>3,
#   "contact"=>2,
#   "about"=>1,
#   "index"=>1,
#   "about/2"=>1}