我想在powerapps中添加按Enter键的操作（与按钮相同）

Question

我正在 PowerApps 中创建一个项目。我需要一项功能的帮助。我想要按钮和按键盘上的 Enter 键来执行相同的操作。

我是一个完全的初学者，我不知道如何应对。 这是我的代码：

` 登录屏幕作为屏幕： 背景图片：=bg1k 图像位置：=ImagePosition.Fill 可见： | =设置(labeltxt,假); 设置（lblview，TextMode.密码）；

    Container1 As groupContainer.manualLayoutContainer:
        DropShadow: =DropShadow.ExtraBold
        Fill: =RGBA(255, 255, 255, 1)
        Height: =600
        RadiusBottomLeft: =10
        RadiusBottomRight: =10
        RadiusTopLeft: =10
        RadiusTopRight: =10
        X: =450
        Y: =63
        ZIndex: =1

        personalNumbertxt As text:
            BorderThickness: =1
            Default: =""
            Height: =60
            HintText: ="Enter your personal number here"
            OnChange: |
                =
            OnSelect: =Set(labeltxt,false)
            PaddingBottom: =20
            PaddingLeft: =35
            PaddingTop: =20
            RadiusBottomLeft: =0
            RadiusBottomRight: =0
            RadiusTopLeft: =0
            RadiusTopRight: =0
            Width: =447
            X: =28
            Y: =154
            ZIndex: =1

        pintxt As text:
            BorderThickness: =1
            Default: =""
            Height: =60
            HintText: ="Enter your PIN code here"
            Mode: =lblview
            PaddingLeft: =35
            RadiusBottomLeft: =0
            RadiusBottomRight: =0
            RadiusTopLeft: =0
            RadiusTopRight: =0
            Width: =450
            X: =28
            Y: =251
            ZIndex: =2

        loginFormlbl As label:
            Align: =Align.Center
            FontWeight: =FontWeight.Bold
            Height: =50
            Size: =24
            Text: ="Login Form"
            Width: =450
            X: =25
            Y: =50
            ZIndex: =3

        incorrectlbl As label:
            Align: =Align.Center
            Color: =RGBA(118, 0, 0, 1)
            Height: =59
            Size: =11
            Text: ="Incorrect personal number or PIN!"
            Visible: =labeltxt
            Width: =450
            X: =25
            Y: =371
            ZIndex: =4

        loginbtn As button:
            Height: =43
            OnSelect: |
                =Set(
                    userrolevalue, 
                    LookUp( 
                        loginns, 
                        'Personal number' = personalNumbertxt.Text And PIN = Value(pintxt.Text)
                    )
                );
                If(
                    IsBlankOrError(userrolevalue),  //ak neplatí
                    Notify("Incorrect Username or Password");
                    Set(labeltxt, true),
                    Navigate(categoryScreen)   //ak platí
                );
                Reset(personalNumbertxt); //po overení užívateľa!! čiže akokoľvek 
                Reset(pintxt);
            RadiusBottomLeft: =5
            RadiusBottomRight: =5
            RadiusTopLeft: =5
            RadiusTopRight: =5
            Text: ="Login"
            Width: =239
            X: =130
            Y: =456
            ZIndex: =5

        iconUser As icon.AddUser:
            Color: =RGBA(102, 102, 102, 1)
            Height: =60
            Icon: =Icon.AddUser
            PaddingLeft: =7
            Width: =25
            X: =28
            Y: =154
            ZIndex: =6

        iconView As icon.View:
            Color: =RGBA(128, 128, 128, 1)
            Height: =36
            Icon: =Icon.View
            OnSelect: =Set(lblview,TextMode.SingleLine)
            PaddingRight: =10
            Width: =36
            X: =426
            Y: =263
            ZIndex: =7

        iconLock As icon.Lock:
            Color: =RGBA(128, 128, 128, 1)
            Height: =60
            Icon: =Icon.Lock
            PaddingLeft: =7
            Width: =25
            X: =28
            Y: =251
            ZIndex: =8

`

Answer 1

不幸的是，默认情况下，Microsoft Power Apps 不支持“输入键”功能。

有一些解决方法可以使其正常工作，如本线程中所述，Power Apps - 使用 Enter 键提交表单：

您可以先多次按“Tab”键，直到选择“提交”按钮，然后按“Enter”触发此按钮并提交表单。

---

Tab 键应按逻辑顺序导航至交互元素。您可以使用逻辑应用程序结构并相应地设置每个控件的TabIndex属性来创建它。

来源：创建可访问的画布应用程序