每组每项的最新记录

问题描述 投票:1回答:2

简化问题:在表“ table1”中,我们有列:RowID,ItemID,BranchID,RoomID,Date,Qty

我正在尝试在每个BranchID中的每个RoomID中检索ItemID的最后一个数量。

一旦完成,计划是将table1联接到ItemIDTable,BranchIDTable,RoomIDTable以获取ID的名称。

通过使用MAX(Date),我得到了仅位于一个RoomID中的ItemID的数量,但是,如果ItemID在多个RoomID中,则函数MAX(Date)返回所有房间中的最新记录,而我需要每个房间的最新信息。

ItemID = 50和BranchID = 4的数据集:

+ -------- + ---------- + -------- + ----- + -------------- ------- + ------------ + ------------ + -------------- +| ItemID | BranchID | RoomID |数量日期| ItemIDName | RoomIDNAme | BranchIDName |+ -------- + ---------- + -------- + ----- + -------------- ------- + ------------ + ------------ + -------------- +| 50 | 4 | 1 | 7 | 2019-12-12 13:30:15 | ItemA |房间B |分公司B || 50 | 4 | 2 | 5 | 2019-12-12 13:30:20 | ItemA |房间A |分公司B || 50 | 4 | 2 | 8 | 2019-12-12 13:30:25 | ItemA |房间A |分公司B |+ -------- + ---------- + -------- + ----- + -------------- ------- + ------------ + ------------ + -------------- +

我得到的结果(它从两个RoomID中选择了最新的一个:]

+ -------- + ---------- + -------- + ----- + -------------- ------- + ------------ + ------------ + -------------- +| ItemID | BranchID | RoomID |数量日期| ItemIDName | RoomIDNAme | BranchIDName |+ -------- + ---------- + -------- + ----- + -------------- ------- + ------------ + ------------ + -------------- +| 50 | 4 | 2 | 8 | 2019-12-12 13:30:25 | ItemA |房间A |分公司B |+ -------- + ---------- + -------- + ----- + -------------- ------- + ------------ + ------------ + -------------- +

预期(每个RoomID的最新数量):

+ -------- + ---------- + -------- + ----- + -------------- ------- + ------------ + ------------ + -------------- +| ItemID | BranchID | RoomID |数量日期| ItemIDName | RoomIDNAme | BranchIDName |+ -------- + ---------- + -------- + ----- + -------------- ------- + ------------ + ------------ + -------------- +| 50 | 4 | 1 | 7 | 2019-12-12 13:30:15 | ItemA |房间B |分公司B || 50 | 4 | 2 | 8 | 2019-12-12 13:30:25 | ItemA |房间A |分公司B |+ -------- + ---------- + -------- + ----- + -------------- ------- + ------------ + ------------ + -------------- +

查询本身:

选择table1.ItemID,table1.BranchID,table1.RoomID,table1。数量table1.Date,ItemIDTable.ItemIDName,RoomIDTable.RoomIDName,BranchIDTable.BranchIDName从表1内联接ItemIDTable ON table1.ItemID = ItemIDTable.ItemID内部联接RoomIDTable ON table1.RoomID = RoomIDTable.RoomID内联接Table1.BranchID = BranchIDTable.BranchID上的BranchIDTable哪里(表1.日期输入(SELECT MAX(日期)从表1其中(ItemID = table1.ItemID)和(BranchID = table1.BranchID)))订购table1.ItemID

我已尝试简化和简化标题以使其更具可读性。无论是使此查询正常工作还是使用更好的方法,A都会感谢您对此的任何见解。

sql sql-server greatest-n-per-group
2个回答
0
投票

您可以使用ROW_NUMBER()窗口功能:

DECLARE @Tab TABLE (ItemID INT, BranchID INT, RoomID INT, Qty INT,Dt datetime,ItemIDName varchar(10),RoomIDNAme varchar(10),BranchIDName varchar(10))
insert @tab
values
(50,4,1,7,'2019-12-12 13:30:15','ItemA','RoomB','BranchB'),
(50,4,2,5,'2019-12-12 13:30:20','ItemA','RoomA','BranchB'),
(50,4,2,8,'2019-12-12 13:30:25','ItemA','RoomA','BranchB')

 SELECT *
 FROM(
     SELECT row_number() over(partition by itemid, branchid, roomid order by dt desc) rn, *
     FROM @Tab
     ) t
 WHERE t.rn = 1

或与您的查询:

SELECT *
FROM(
    SELECT ROW_NUMBER() OVER(PARTITION BY table1.ItemID, table1.BranchID, table1.RoomID, ORDER BY table1.Date DESC) rn
        table1.ItemID, 
        table1.BranchID, 
        table1.RoomID, 
        table1.Qty, 
        table1.Date, 
        ItemIDTable.ItemIDName, 
        RoomIDTable.RoomIDName, 
        BranchIDTable.BranchIDName
    FROM         
        table1 INNER JOIN
        ItemIDTable ON table1.ItemID = ItemIDTable.ItemID INNER JOIN
        RoomIDTable ON table1.RoomID = RoomIDTable.RoomID INNER JOIN
        BranchIDTable ON table1.BranchID = BranchIDTable.BranchID
    WHERE     
        (table1.Date IN
            (
                SELECT     MAX(Date)
                FROM          table1
                WHERE      (ItemID = table1.ItemID) AND (BranchID = table1.BranchID)
            )
        )
  ) t
 WHERE t.rn = 1
ORDER BY 
    table1.ItemID

0
投票

我正在尝试在每个BranchID中的每个RoomID中检索ItemID的最后一个数量。

您使用关联子查询进行过滤的意图在我看来是个好主意。但是,您的WHERE子句不能完全满足您的要求:它似乎缺少RoomID上的条件:

WHERE  
    (table1.Date IN
        (
            SELECT     MAX(Date)
            FROM          table1
            WHERE      (ItemID = table1.ItemID) AND (BranchID = table1.BranchID)
        )
    )

此外,由于子查询无论如何都会返回最大一条记录,因此该条件应重写为使用等式而不是IN。请注意,此处大多数括号是多余的。最后,我建议使用表别名来消除子查询中的列名称的歧义。

考虑:

SELECT     
    t1.ItemID, 
    t1.BranchID, 
    t1.RoomID, 
    t1.Qty, 
    t1.Date, 
    i.ItemIDName, 
    r.RoomIDName, 
    b.BranchIDName
FROM         
    table1 t1
    INNER JOIN ItemIDTable i ON t1.ItemID = i.ItemID
    INNER JOIN RoomIDTable r ON t1.RoomID = r.RoomID
    INNER JOIN BranchIDTable ON t1.BranchID = b.BranchID
WHERE t1.Date = (
    SELECT MAX(t11.Date)
    FROM   table1 t11
    WHERE 
        t11.ItemID = t1.ItemID
        AND t11.BranchID = t1.BranchID
        AND t11.RoomID = t1.RoomID
    )
ORDER BY t1.ItemID
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