我想弹出导航堆栈上的第三个视图回到第一个视图。
我知道如何一次弹出一个视图：
[self.navigationController popViewControllerAnimated:YES];
但我怎么一次做两个呢？
您也可以尝试在导航控制器堆栈之间跳转
NSMutableArray *allViewControllers = [NSMutableArray arrayWithArray:[self.navigationController viewControllers]];
for (UIViewController *aViewController in allViewControllers) {
if ([aViewController isKindOfClass:[RequiredViewController class]]) {
[self.navigationController popToViewController:aViewController animated:NO];
}
}
NSMutableArray *newStack = [NSMutableArray arrayWithArray:[self.navigationController viewControllers]];
[newStack removeLastObject];
[newStack removeLastObject];
[self.navigationController setViewControllers:newStack animated:YES];
在Swift 3中，您可以从导航控制器中弹出一个，两个或更多个视图控制器
let viewControllers = self.navigationController!.viewControllers as [UIViewController]
for aViewController:UIViewController in viewControllers {
if aViewController.isKind(of: FromWhereYouWantToGoController.self) {
_ = self.navigationController?.popToViewController(aViewController, animated: true)
}
}
这里FromWhereYouWantToGoController是目标控制器。希望能帮助到你。
您可以传递初始视图控制器（您想要返回的控制器），然后在最后一个视图中调用此行：
[self.navigationController popToViewController:yourInitialViewController animated:YES];
L.
我在这里没有看到这个答案。如果你只想弹出一些（不是一直到root），你可以通过self.navigationController.viewControllers迭代检查类类型，或者你有一个引用使用：
for (UIViewController *aViewController in self.navigationController.viewControllers) {
if ([aViewController isKindOfClass:[SMThumbnailViewController class]]) {
[self.navigationController popToViewController:aViewController animated:YES];
}
}
您可以弹回到根视图控制器
[self.navigationController popToRootViewControllerAnimated:YES];
或者，如果要弹出的视图不是第一个，则需要在上一个视图中再次弹出viewWillAppear
这是我用来返回X ViewControllers的一个小函数：
-(void)backMultiple:(id)data {
int back = 2; //Default to go back 2
int count = [self.navigationController.viewControllers count];
if(data[@"count"]) back = [data[@"count"] intValue];
//If we want to go back more than those that actually exist, just go to the root
if(back+1 > count) {
[self.navigationController popToRootViewControllerAnimated:YES];
}
//Otherwise go back X ViewControllers
else {
[self.navigationController popToViewController:[self.navigationController.viewControllers objectAtIndex:count-(back+1)] animated:YES];
}
}
Swift版本（Swift 1.2 / Xcode 6.3.1）弹出两次或更多次
var viewControllers = self.navigationController?.viewControllers
viewControllers?.removeLast()
viewControllers?.removeLast()
self.navigationController?.setViewControllers(viewControllers, animated: true)
要么
var viewControllers = self.navigationController?.viewControllers
var viewsToPop = 2
var end = (viewControllers?.count)!
var start = end - viewsToPop
viewControllers?.removeRange(Range<Int>(start: start, end: end))
self.navigationController?.setViewControllers(viewControllers, animated: true)
您可以使用UIViewControllers的堆栈。 1.获取堆栈中所有viewControllers的数组。 2.遍历整个数组并找到所需的viewController 通过匹配类类型。 3.弹出viewController。
func popToSpecificViewC
{
let viewControllers: [UIViewController] = self.navigationController!.viewControllers as [UIViewController];
for viewController:UIViewController in viewControllers
{
if viewController.isKind(of: WelcomeViewC.self)
{
_ = self.navigationController?.popToViewController(viewController, animated: true)
}
}
}
Swift 4.2
在你的navigationController?.viewControllers上你可以检查你的导航控制器上的viewControllers，所以你只需要弹出你想要的位置，就像那样：
navigationController?.popToViewController(navigationController?.viewControllers[1], animated: true)
其中1是我想要弹出的ViewController的位置。
这里有两个UINavigationController扩展可以解决您的问题。我建议使用弹出到特定类的UIViewController的第一个：
extension UINavigationController {
func popToViewController(ofClass: AnyClass, animated: Bool = true) {
if let vc = viewControllers.filter({$0.isKind(of: ofClass)}).last {
popToViewController(vc, animated: animated)
}
}
func popViewControllers(viewsToPop: Int, animated: Bool = true) {
if viewControllers.count > viewsToPop {
let vc = viewControllers[viewControllers.count - viewsToPop - 1]
popToViewController(vc, animated: animated)
}
}
}
并像这样使用它：
// pop to SomeViewController class
navigationController?.popToViewController(ofClass: SomeViewController.self)
// pop 2 view controllers
navigationController?.popViewControllers(viewsToPop: 2)
您可以使用popToRootViewControllerAnimated弹出“root”（第一个）视图控制器：
[self.navigationController popToRootViewControllerAnimated:YES];
// If you want to know what view controllers were popd:
// NSArray *popdViewControllers = [self.navigationController popToRootViewControllerAnimated:YES];
UINavigationController Reference：
弹出除根视图控制器之外的堆栈上的所有视图控制器并更新显示。
回报价值 从堆栈弹出的一组视图控制器。
[self.navigationController popToViewController:[self.navigationController.viewControllers objectAtIndex:1] animated:YES];
objectAtIndex：1 - >您可以传递要弹出的索引
Swift 2 - xCode 7.3
这可能是弹出UIViewControllers的一个非常有用的扩展：
extension UINavigationController {
func popToViewControllerOfType(classForCoder: AnyClass) {
for controller in viewControllers {
if controller.classForCoder == classForCoder {
popToViewController(controller, animated: true)
break
}
}
}
func popViewControllers(controllersToPop: Int, animated: Bool) {
if viewControllers.count > controllersToPop {
popToViewController(viewControllers[viewControllers.count - (controllersToPop + 1)], animated: animated)
} else {
print("Trying to pop \(controllersToPop) view controllers but navigation controller contains only \(viewControllers.count) controllers in stack")
}
}
}
如果你只是想一次弹出2，因为你的rootViewController是“更深”，那么你可以考虑在UIviewController中添加一个类别，例如：
#import <UIKit/UIKit.h>
@interface UINavigationController (popTwice)
- (void) popTwoViewControllersAnimated:(BOOL)animated;
@end
#import "UINavigationController+popTwice.h"
@implementation UINavigationController (popTwice)
- (void) popTwoViewControllersAnimated:(BOOL)animated{
[self popViewControllerAnimated:NO];
[self popViewControllerAnimated:animated];
}
@end
在您的实现中的某处导入类别#import "UINavigationController+popTwice.h"并使用这行代码一次弹出2个控制器：
[self.navigationController popTwoViewControllersAnimated:YES];
那不是很好吗？ :)
你也可以尝试这个： -
[self.navigationController popToViewController:yourViewController animated:YES];
//viewIndex = 1;
//viewIndex = 2;
//viewIndex = 3;
// **[viewControllers objectAtIndex: *put here your viewindex number*]
NSArray *viewControllers = [self.navigationController viewControllers];
[self.navigationController popToViewController:[viewControllers objectAtIndex:viewIndex] animated:NO];
斯威夫特4：
func popViewControllerss(popViews: Int, animated: Bool = true) {
if self.navigationController!.viewControllers.count > popViews
{
let vc = self.navigationController!.viewControllers[self.navigationController!.viewControllers.count - popViews - 1]
self.navigationController?.popToViewController(vc, animated: animated)
}
}
然后使用此方法
self.popViewControllerss(popViews: 2)