TypeScript>函数组件不能给定引用。尝试访问此引用将失败。您是要使用React.forwardRef（）吗？

Question

我尝试在React，Typescript和ant ui上创建功能组件。但是，当我创建子组件时，我会发出警告-“无法为功能组件提供引用。尝试访问该引用将失败。您是要使用React.forwardRef（）吗？”。请告诉我我在哪里犯错了？

CreateCounterpartyComponent：

const CreateCounterpartyComponent: React.FC<FormComponentProps> = props => {
  const GET_ALL = gql`
    query {
      types {
        value: id
        name: full_name
      }
    }
  `;
  const { getFieldDecorator } = props.form;
  const handleSubmit = (e: React.FormEvent) => {
    e.preventDefault();
    console.log(e);
  };
  const changeHandler = (e:number) => {
    console.log(e)
  }
  const { loading, data } = useQuery(GET_ALL);
  if (loading) return <Loader />;
  return (
    <div>
      <Form onSubmit={handleSubmit}>
        <Form.Item hasFeedback>
          {getFieldDecorator('address', {
            rules: [{ required: true, message: 'Address?' }],
          })(<CustomSeletor items={data.types} width="20%" changeEvent={(e)=>changeHandler(e)}/>)}
        </Form.Item>
        <Form.Item>
          <Button type="primary" htmlType="submit" className="login-form-button">
            Send
          </Button>
        </Form.Item>
      </Form>
    </div>
  );
};

export const CreateCounterparty = Form.create()(CreateCounterpartyComponent);

CustomSeletor：

const { Option } = Select;

interface IProps {
  items: ISelectorProps[];
  width: string;
  changeEvent(e:number):void;
}

export const CustomSeletor: React.FC<IProps> = ({ items, width, changeEvent }) => {
  const mystyles = {
    width: width,
  };
  const handleChange = (e:number) => {
      changeEvent(e)
  }
  const options = items.map(({ value, name }) => <Option key={value} value={value}>{name}</Option>);
  return (
    <Select style={mystyles} onChange={handleChange}>
      {options}
    </Select>
  );
};

Answer 1

您正在使用antd。如this page上指定：